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One hour after Yolanda started walking from X to Y, a distan [#permalink]

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28 Jan 2004, 16:43

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One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and Bobт's was 4 miles per hour, how many miles had Bob walked when they met?

When bob starts walking The distance between them is 45-3 = 42 miles
If they meet at time t then Yolanda would have walked
X/3 minutes and Bob would have walked (42-X)/4 mins
X/3 = (42-X)/4 so X = 18
Bob would have walked 42-18 = 24 miles.

One hour after Yolander started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolander’s walking rate was 3 miles per hour and Bob’s was 4 miles per hour, how many miles had Bob walked when they met? ○ 24 ○ 23 ○ 22 ○ 21 ○ 19.5

When B started walking Y already has covered 3 miles out of 45, hence the distance at that time between them was 45-3=42 miles.

Combined rate of B and Y was 3+4=7 miles per hour, hence they would meet each other in 42/7=6 hours. In 6 hours B walked 6*4=24 miles.

Re: One hour after Yolanda started walking from X to Y, a [#permalink]

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18 Sep 2013, 18:03

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One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 3 miles per hour and Bobâs was 4 miles per hour, how many miles had Bob walked when they met?

One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 3 miles per hour and Bobâs was 4 miles per hour, how many miles had Bob walked when they met?

A. 24 B. 23 C. 22 D. 21 E. 19.5

Let t be the number of hours that Bob had walked when he met Yolanda. Then, when they met, Bob had walked 4t miles and Yolanda had walked 3(t + 1) miles. These distances must sum to 45 miles, so 4t + 3(t + 1) = 45, which may be solved for t as follows 4t + 3(t + 1) = 45 4t + 3t + 3 = 45 7t = 42 T = 6 (hours) Therefore, Bob had walked 4t = 4(6) = 24 miles when they met. The best answer is A.
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Re: One hour after Yolanda started walking from X to Y, a distan [#permalink]

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19 Dec 2015, 06:12

Hello from the GMAT Club BumpBot!

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Re: One hour after Yolanda started walking from X to Y, a distance of 45 m [#permalink]

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12 Oct 2016, 12:20

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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One hour after Yolanda started walking from X to Y, a distance of 45 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and Bobт's was 4 miles per hour, how many miles had Bob walked when they met?

(A) 24 (B) 23 (C) 22 (D) 21 (E) 19.5

1. In 1 hr Yolanda would have walked 3 miles 2. Yolanda and Bob both walk simultaneously after that and move towards each other. 3. They would have met after (45-3)/(3+4)= 6hrs 4. In 6 hrs, Bob would have walked , 6*4=24 miles
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