Tridhipal
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One large circle and two identical smaller circles are inscribed inside a rectangle as shown above. A and B are the points of intersection of the long side of the rectangle and the large and small circles (respectively.) If the short side of the rectangle is 8, what is AB?
a 4
b 2√5
c 4√2
d 6
e 2√10
Hi...
What can you make out of the RADIUS..The larger circle's radius is
twice of smaller one's..
Larger one =\(\frac{8}{2}=4\) and smaller one is 2..
Now join the centre of larger and the smaller one as shown
This line will be = sum of radius = 4+2=6
Now draw a line PARALLEL to AB and bisecting the radius drawn from A at D..
Now you have a right angle triangle whose hypotenuse is 6 and one side is 4-2=2
Third side, CD, which will also be equal to AB = \(√(6^2-2^2)=√32=4√2\)
C
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