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vivektripathi
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stallone
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stallone
well :

i get 1/5 for all of them :shock:

every time you pick one, the # of total decreases, since no replacement.
so when you pick the second one to be defective there is 1 defective out of 4 total.
when you pick the 3rd to be defective, you have already picked two good one before, so the total should be 3, and 1 of these 3 is defective.
i hope this helps. :lol:
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vivektripathi
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vivektripathi
One of 5 pens is faulty. They are tested one at a time, what is the probability that the faulty pen is :
(a) 1th first one tested (b) the 2nd one testedt
(b) the rd one tested (d) the last one tested

I am not sure but stem says that there are five pens places I I I I I
1 2 3 4 5
and if pick 1st or 2nd or third or last and test it the probability will remain same i.e. 1/5.



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