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MT1302
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Out of a stock of 10 microphones, an electronics store sold more than 20 Mar 2024, 08:25
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55% (hard)

Question Stats:

69% (02:35) correct 31% (02:46) wrong based on 266 sessions

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­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 2 microphones at $Y.
(2) Y= $60­
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C
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stne
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Out of a stock of 10 microphones, an electronics store sold more than 21 Mar 2024, 02:15
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Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60


 
Show more
­If profit for \(2\)  Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\) 

INSUFF.

1+2 

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a  typo in statement 1. Thank you.­
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Out of a stock of 10 microphones, an electronics store sold more than 21 Mar 2024, 02:26
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stne

Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60



 
­If profit for \(2\)  Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\) 

INSUFF.

1+2 

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a  typo in statement 1. Thank you.­
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­______________________
Fixed the typo. Thank you.
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Out of a stock of 10 microphones, an electronics store sold more than 29 May 2024, 00:46
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stne

Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60



 
­If profit for \(2\)  Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\) 

INSUFF.

1+2 

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a  typo in statement 1. Thank you.­
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­Can't we solve I alone by x + y = 10 mics? Substitution of 2 variables with 2 equations.
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Out of a stock of 10 microphones, an electronics store sold more than 29 May 2024, 06:18
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renzosm93

stne

Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60






 
­If profit for \(2\)  Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\) 

INSUFF.

1+2 

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a  typo in statement 1. Thank you.­
­Can't we solve I alone by x + y = 10 mics? Substitution of 2 variables with 2 equations.


 
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­Can you list the two equations that you are talking about. Thank you. 
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Out of a stock of 10 microphones, an electronics store sold more than 07 Jul 2024, 16:32
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KarishmaB chetan2u It was never mentioned that the store sold for X$ each . Why do we need to consider 8x here ? I am getting B as the answer.
stne

Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60



 
­If profit for \(2\)  Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\) 

INSUFF.

1+2 

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a  typo in statement 1. Thank you.­
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Out of a stock of 10 microphones, an electronics store sold more than 07 Jul 2024, 18:42
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Yes, I would agree the question could have been written in a better way. Microphones changes to pair of microphones somewhere in between. And also as you wrote, the wordings do not point towards x being the average price. It could easily mean the total amount.
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Out of a stock of 10 microphones, an electronics store sold more than 07 Jul 2024, 21:03
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chetan2u Sir , Would you like to provide your explanation / soultion to this ? KarishmaB
chetan2u
Yes, I would agree the question could have been written in a better way. Microphones changes to pair of microphones somewhere in between. And also as you wrote, the wordings do not point towards x being the average price. It could easily mean the total amount.
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Out of a stock of 10 microphones, an electronics store sold more than 12 Feb 2025, 20:38
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Hi, stne chetan2u

How does the profit for 2 =40? I think it should be 20.
And, we'll get the sales revenue 600.

Considering statement 2,

If we let the number of microphones sold at $x be n

Then we can put it this way;

nx+ y(10-n)=600
nx+60(10)-60n=600
nx-60n=0
nx=60n
x=60

Where am I going wrong in logic?
stne

Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60


­If profit for \(2\) Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\)

INSUFF.

1+2

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a typo in statement 1. Thank you.­
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Out of a stock of 10 microphones, an electronics store sold more than 13 Feb 2025, 14:30
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nishantswaft
Hi, stne chetan2u

How does the profit for 2 =40? I think it should be 20.
And, we'll get the sales revenue 600.

Considering statement 2,

If we let the number of microphones sold at $x be n

Then we can put it this way;

nx+ y(10-n)=600
nx+60(10)-60n=600
nx-60n=0
nx=60n
x=60

Where am I going wrong in logic?
stne

Gangadhar111990
­Out of a stock of 10 microphones, an electronics store sold more than half of the microphones for $X and the remainder for $Y. If the average cost of the microphones to the store was $50 and the store's average profit on a pair of microphones was $20, what was the value of X?

(1) The store sold 20 microphones at $Y.
(2) Y= $60


­If profit for \(2\) Mics is \(40\) then profit for \(10\) mics is \(200\)

Hence total sales revenue is \(700\)

(1) The store sold 2 microphones at $Y.

\(8x+2y =700\)

Clearly insuff as \(x\) and \(y\) can have many values.

(2) Y= $60

We do not know how many were sold for \($60\)

\(8x +2*60 = 700\)

\(7x+ 3*60 =700\)

etc.

We will get different values of \(x\)

INSUFF.

1+2

\(8x+2*60 =700\)

\(x=72.5 \)

SUFF.

Ans C

Hope it helped.

Gangadhar111990, Bunuel There is a typo in statement 1. Thank you.­
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Question says average profit of two mics is \(20\) thus total profit of two mics is \(2*20 = 40\) The key word is average.

How did you conclude total profit for \(2 \) mics is \(20\)? When question says average profit is \(20.\)

How can average profit = total profit?

Hope it helped.
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Out of a stock of 10 microphones, an electronics store sold more than 13 Feb 2025, 19:26
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Understood the difference. Thanks!
stne
nishantswaft
Hi, stne chetan2u

How does the profit for 2 =40? I think it should be 20.
And, we'll get the sales revenue 600.

Considering statement 2,

If we let the number of microphones sold at $x be n

Then we can put it this way;

nx+ y(10-n)=600
nx+60(10)-60n=600
nx-60n=0
nx=60n
x=60

Where am I going wrong in logic?
Question says average profit of two mics is \(20\) thus total profit of two mics is \(2*20 = 40\) The key word is average.

How did you conclude total profit for \(2 \) mics is \(20\)? When question says average profit is \(20.\)

How can average profit = total profit?

Hope it helped.
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