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Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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05 Jun 2020, 07:24
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Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games? A. 2 B. 5 C. 6 D. 7 E. Cannot be determined
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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05 Jun 2020, 20:21
Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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05 Jun 2020, 20:49
chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B Have you consider people like only Badminton and only Soccer as Null? Posted from my mobile device



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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05 Jun 2020, 21:09
yashikaaggarwal wrote: chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B Have you consider people like only Badminton and only Soccer as Null? Posted from my mobile deviceYes, because that is what the data suggests.
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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06 Jun 2020, 02:42
chetan2u wrote: yashikaaggarwal wrote: chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B Have you consider people like only Badminton and only Soccer as Null? Posted from my mobile deviceYes, because that is what the data suggests. Where in the question it is given that only badminton and only soccer each is zero, when there is also option cannot be determined?



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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06 Jun 2020, 04:53
IMO Echetan2u: Sir it is given that All three games = 3, and Badminton and Soccer =5, how you deduced that it actually should be 2 (53) and why other values as 0. Can you please help in clarifying doubts.
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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06 Jun 2020, 04:59
Bunuel Sir Can You Post Official Explanation to the question. Posted from my mobile device



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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06 Jun 2020, 05:17
NitishJain wrote: IMO Echetan2u: Sir it is given that All three games = 3, and Badminton and Soccer =5, how you deduced that it actually should be 2 (53) and why other values as 0. Can you please help in clarifying doubts. I would agree the question is not worded in the best possible way. But if this question is in GMAT, I will answer B for two reasons 1) Almost all questions on GMAT will not have an option that states ‘cannot be determined.’ 2) There is nothing in the question that states that there is some more information than what is given. Of course, as I said there is a bit of confusion in the wordings.
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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06 Jun 2020, 05:22
chetan2u wrote: NitishJain wrote: IMO Echetan2u: Sir it is given that All three games = 3, and Badminton and Soccer =5, how you deduced that it actually should be 2 (53) and why other values as 0. Can you please help in clarifying doubts. I would agree the question is not worded in the best possible way. But if this question is in GMAT, I will answer B for two reasons 1) Almost all questions on GMAT will not have an option that states ‘cannot be determined.’ 2) There is nothing in the question that states that there is some more information than what is given. Of course, as I said there is a bit of confusion in the wordings. I agree with your point 1 sir. Since this question has option E as "Cannot be determined", it leaves little room for assumption. I can still agree with other values as 0, but how did you arrive at Badminton and Soccer=2?
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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06 Jun 2020, 05:39
NitishJain wrote: chetan2u wrote: NitishJain wrote: IMO Echetan2u: Sir it is given that All three games = 3, and Badminton and Soccer =5, how you deduced that it actually should be 2 (53) and why other values as 0. Can you please help in clarifying doubts. I would agree the question is not worded in the best possible way. But if this question is in GMAT, I will answer B for two reasons 1) Almost all questions on GMAT will not have an option that states ‘cannot be determined.’ 2) There is nothing in the question that states that there is some more information than what is given. Of course, as I said there is a bit of confusion in the wordings. I agree with your point 1 sir. Since this question has option E as "Cannot be determined", it leaves little room for assumption. I can still agree with other values as 0, but how did you arrive at Badminton and Soccer=2? There are 5 like to play B and S. Now this 5 will consist of 1) only B+S 2) B+S+V, which is given as 3. So only B+S=53=2
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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07 Jun 2020, 01:26
Its really strange how did you assume something as there may be other possibility. I read you explanation, sir! But I didn't get how assumption is applicable in quant section. In my opinion, what if only B is 2 and Only S is 1, then I would get 2 as answer. Or B and S can have 1 and 2 respectively. Q asks number of people who don't like to play any of the 3 games. Means number of students completely outside of shown circles. Please explain. chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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07 Jun 2020, 01:34
gvij2017 wrote: Its really strange how did you assume something as there may be other possibility. I read you explanation, sir! But I didn't get how assumption is applicable in quant section. In my opinion, what if only B is 2 and Only S is 1, then I would get 2 as answer. Or B and S can have 1 and 2 respectively. Q asks number of people who don't like to play any of the 3 games. Means number of students completely outside of shown circles. Please explain. chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B It's a pretty straight forward sum in which there is nothing to assume and there is no problem in the wording of the sum. Answer is cannot be determined. You can assume anything in Quant section. Posted from my mobile device



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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07 Jun 2020, 01:36
gurmukh wrote: gvij2017 wrote: Its really strange how did you assume something as there may be other possibility. I read you explanation, sir! But I didn't get how assumption is applicable in quant section. In my opinion, what if only B is 2 and Only S is 1, then I would get 2 as answer. Or B and S can have 1 and 2 respectively. Q asks number of people who don't like to play any of the 3 games. Means number of students completely outside of shown circles. Please explain. chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B It's a pretty straight forward sum in which there is nothing to assume and there is no problem in the wording of the sum. Answer is cannot be determined. You can assume anything in Quant section. Posted from my mobile deviceSorry I wanted to write you cannot assume anything in Quant.



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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07 Jun 2020, 02:13
gvij2017 wrote: Its really strange how did you assume something as there may be other possibility. I read you explanation, sir! But I didn't get how assumption is applicable in quant section. In my opinion, what if only B is 2 and Only S is 1, then I would get 2 as answer. Or B and S can have 1 and 2 respectively. Q asks number of people who don't like to play any of the 3 games. Means number of students completely outside of shown circles. Please explain. chetan2u wrote: Bunuel wrote: Out of the 14 people in a group, 3 like to play Badminton, Soccer and Volleyball. If there are 7 people in the group who like to play Volleyball and 5 who like to play Badminton and Soccer, what is the number of people who do not like to play any of the 3 games?
A. 2 B. 5 C. 6 D. 7 E. Cannot be determined We can draw the circles as shown.. All three games = 3. So only B+S=53=2 V+(any one game only or none)=73=4 Total who play game=3+2+4=9. So, the number of people who do not like to play any of the 3 games = 149=5. B Hi Yes, we are not supposed to assume anything, and nothing has been assumed. If you say there is something more than what is given, then you are assuming. The details you are looking at is important for DS question. Because traps lie in these kind of lines. They give you that there are 2 red balls and 2 white balls and we are looking at the probability of picking red. Of course we would require to know the total balls or that no other colour is present. But if in a PS question, I give you that there are 2 red balls and 2 white balls, and you have to find the same probability. Will you say that it cannot be determined because there can be other colours too. No, you cannot as you have to work on data given. Same is the case here. If some data is given, why should I take that the data is inadequate if there is nothing in the question stem that tells me that there have to be some playing soccer alone ? But if it were DS and I had this data , I would mark E the same way as I would do it for red and white balls example. Finally, as I have written, you will not find such wordings in GMAT.
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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07 Jun 2020, 02:36
chetan2u wrote: NitishJain wrote: IMO Echetan2u: Sir it is given that All three games = 3, and Badminton and Soccer =5, how you deduced that it actually should be 2 (53) and why other values as 0. Can you please help in clarifying doubts. I would agree the question is not worded in the best possible way. But if this question is in GMAT, I will answer B for two reasons 1) Almost all questions on GMAT will not have an option that states ‘cannot be determined.’ 2) There is nothing in the question that states that there is some more information than what is given. Of course, as I said there is a bit of confusion in the wordings. Sir, going by your logic suppose it is given in the sum that there are 14 balls in the bag and there are 5 red balls in the bag, find the probability of taking out yellow balls, will you assume that all rest of the balls in the bag are yellow and also when one of the option is cannot be determined. Also if you are talking about that there is no such option in GMAT then you are also assuming that they can't give such option because nowhere GMAC mentions that there cannot be a option like this. Posted from my mobile device



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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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07 Jun 2020, 04:24
gurmukh wrote: chetan2u wrote: NitishJain wrote: IMO Echetan2u: Sir it is given that All three games = 3, and Badminton and Soccer =5, how you deduced that it actually should be 2 (53) and why other values as 0. Can you please help in clarifying doubts. I would agree the question is not worded in the best possible way. But if this question is in GMAT, I will answer B for two reasons 1) Almost all questions on GMAT will not have an option that states ‘cannot be determined.’ 2) There is nothing in the question that states that there is some more information than what is given. Of course, as I said there is a bit of confusion in the wordings. Sir, going by your logic suppose it is given in the sum that there are 14 balls in the bag and there are 5 red balls in the bag, find the probability of taking out yellow balls, will you assume that all rest of the balls in the bag are yellow and also when one of the option is cannot be determined. Also if you are talking about that there is no such option in GMAT then you are also assuming that they can't give such option because nowhere GMAC mentions that there cannot be a option like this. Posted from my mobile deviceHi Gurmukh, The case you have taken is not the similar to one we are looking at. You are asking for a probability of a thing that is not even given. The example of finding probability of picking a blue out of a bag and it is given that the bag contains 4 blue and 5 black will stand. You are not given any other colour so take it that you have only 2 colours in PS. Why should we read more than what is given in PS? And as I said, this question does not reflect the wording of actual questions.
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Re: Out of the 14 people in a group, 3 like to play Badminton, Soccer and
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