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15 Mar 2018, 08:09
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mahrah
hi...
what is given?
let the apples be A..
1) 4.5 percent failed to pass inspection so \(\frac{95.5}{100} * A\) passed inspection.
2) Of the apples that failed inspection, 2/3 of them were rotten and the rest was unmatured- \(\frac{2}{3} * \frac{4.5}{100} *\)A rotten and \(\frac{1}{3}*\frac{4.5}{100} *A\) unmatured
3)how many of apples inspected last week at the plant were unmatured? = \(\frac{1}{3}*\frac{4.5}{100} *A\)
what we require is A.
lets see the statements..
(1) 450 of apples inspected last week at the orchard failed to pass inspection.
so \(\frac{4.5A}{100} = 450...... A= 10000\)..
suff
(2) 9,550 of apples inspected last week at the orchard passed inspection
so 95.5% of A = 9550..... A = 10000
suff
D
19 Mar 2018, 18:08
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[GMAT math practice question]
What is the reminder when n^2 is divided by 4?
1) When n is divided by 2, the reminder is 1.
2) When n is divided by 3, the reminder is 1.
=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 1 variable (n) and 0 equations, D is most likely to be the answer. So, we should consider each of the conditions on their own first.
Condition 1)
Plugging-in numbers is suggested for remainder questions.
The integers which have a remainder of 1 when divided by 2 are odd.
So,
n: 1, 3, 5, 7, 9, …
and
n^2: 1, 9, 25, 49, 81, …
Each value of n2 has a remainder of 1 when it is divided by 4.
So, condition 1) is sufficient.
Condition 2)
When n = 1, n^2= 1 has a remainder of 1 when it is divided by 4.
When n = 4, n^2=16 has a remainder of 0 when it is divided by 4.
Since we don’t have a unique answer, condition 2) is not sufficient.
Therefore, A is the answer.
Answer: A
If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
What is the reminder when n^2 is divided by 4?
1) When n is divided by 2, the reminder is 1.
2) When n is divided by 3, the reminder is 1.
=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 1 variable (n) and 0 equations, D is most likely to be the answer. So, we should consider each of the conditions on their own first.
Condition 1)
Plugging-in numbers is suggested for remainder questions.
The integers which have a remainder of 1 when divided by 2 are odd.
So,
n: 1, 3, 5, 7, 9, …
and
n^2: 1, 9, 25, 49, 81, …
Each value of n2 has a remainder of 1 when it is divided by 4.
So, condition 1) is sufficient.
Condition 2)
When n = 1, n^2= 1 has a remainder of 1 when it is divided by 4.
When n = 4, n^2=16 has a remainder of 0 when it is divided by 4.
Since we don’t have a unique answer, condition 2) is not sufficient.
Therefore, A is the answer.
Answer: A
If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
22 Mar 2018, 18:03
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[GMAT math practice question]
X is proportional to Y. If Y is increased by 30%, by approximately what percent is X^2 increased?
A. 30%
B. 40%
C. 50%
D. 60%
E. 70%
=>
X = kY for some k.
Since (1.3kY)^2 = 1.69k^2Y^2 = 1.69(kY)^2 = 1.69X^2, we have (1.69X^2 – X^2) / X^2 = 0.69, which is approximately 70%.
Therefore, the answer is E.
Answer: E
X is proportional to Y. If Y is increased by 30%, by approximately what percent is X^2 increased?
A. 30%
B. 40%
C. 50%
D. 60%
E. 70%
=>
X = kY for some k.
Since (1.3kY)^2 = 1.69k^2Y^2 = 1.69(kY)^2 = 1.69X^2, we have (1.69X^2 – X^2) / X^2 = 0.69, which is approximately 70%.
Therefore, the answer is E.
Answer: E
