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P, a positive integer, leaves remainder 83 when divided by 120. What
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P, a positive integer, leaves remainder 83 when divided by 120. What is the remainder when 3P - 300 is divided by 40?
A. 3
B. 9
C. 11
D. 29
E. 31
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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Take a value larger than 120 which will leave a remainder of 83
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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Jagdeesh wrote:
Take a value larger than 120 which will leave a remainder of 83
Hi, I don't understand, please explain!
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P, a positive integer, leaves remainder 83 when divided by 120. What
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Sprincejindal wrote:
Jagdeesh wrote:
Take a value larger than 120 which will leave a remainder of 83
Hi, I don't understand, please explain!
From Stem, P = 120n+83
now,
= 3(120n+83) -300 divided by 40
= 360n+249-300
= 360n-51
here 360n should be divided by 40
so -51 divided by 40 means 29 should be the reminder.
Note: observe that the sign is -51(minus) remainder 11 is a trap answer.
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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How -51 divided by 40 leaves a remainder of 29?
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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tiger66 wrote:
How -51 divided by 40 leaves a remainder of 29?
-51, it should be 80 - 51, hope you get it.
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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Sprincejindal wrote:
Jagdeesh wrote:
Take a value larger than 120 which will leave a remainder of 83
Hi, I don't understand, please explain!
The idea is to find a number that satisfies the question stem. Hence choose a number 'p' that will satisfy the condition.
p / 120 should leave a remainder of 83. Let's assume that the quotient is 1,
p = 120*1 + 83 = 203.
Now, plug in the remainder of the question:
3 * p - 300 = 609 - 300 = 309.
Divide 309 by 40 which will leave a remainder of 29.
Hope this helps.
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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nkmungila wrote:
P, a positive integer, leaves remainder 83 when divided by 120. What is the remainder when 3P - 300 is divided by 40?
We can create the equation P = 120Q + 83
When Q = 1, P = 120 + 83 = 203.
Thus, 3P - 300 = 3(203) - 300 = 309.
309/40 = 7 remainder 29
Answer: D
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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nkmungila wrote:
P, a positive integer, leaves remainder 83 when divided by 120. What is the remainder when 3P - 300 is divided by 40?
Hi..
40 is a factor of 120 lets see 3P-300..
3P will leave a remainder of 3*3=9
and -300 will leave a remainder of 20 as -300 = -4*80
+20 ....
Always remember there is NO negative remainder total remainder = 9+20=29
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What
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nkmungila wrote:
Sprincejindal wrote:
Jagdeesh wrote:
Take a value larger than 120 which will leave a remainder of 83
Hi, I don't understand, please explain!
From Stem, P = 120n+83
now,
= 3(120n+83) -300 divided by 40
= 360n+249-300
= 360n-51
here 360n should be divided by 40
so -51 divided by 40 means 29 should be the reminder.
Note: observe that the sign is -51(minus) remainder 11 is a trap answer.
We can can 83 as p.
In that case the remainder is 9
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Re: P, a positive integer, leaves remainder 83 when divided by 120. What &nbs
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01 Nov 2017, 06:31
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54% (01:16) correct 
