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655-705 (Hard)|   Geometry|      
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 05 Dec 2018, 01:15
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55% (hard)

Question Stats:

71% (03:05) correct 29% (03:10) wrong based on 223 sessions

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P is a point on side AB of a rectangle ABCD, which divides AB in the ratio 5: 3. Q is a point on CD, such that CQ: QD = 3: 1. If the area of rectangle ABCD is 480 sq. units, then what is the area of the quadrilateral ADQP?

    A. 105 sq. units
    B. 150 sq. units
    C. 175 sq. units
    D. 210 sq. units
    E. 270 sq. units

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D
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 05 Dec 2018, 02:30
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P is a point on side AB of a rectangle ABCD, which divides AB in the ratio 5: 3. Q is a point on CD, such that CQ: QD = 3: 1. If the area of rectangle ABCD is 480 sq. units, then what is the area of the quadrilateral ADQP?

    A. 105 sq. units
    B. 150 sq. units
    C. 175 sq. units
    D. 210 sq. units
    E. 270 sq. units

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EgmatQuantExpert :

Hello I tried doing the question but I am not able to get correct answer , my doubt is on the points P & Q are they both dividing the rectangle on same side i.e lengths/ breadth of the rectangle? without figure its becoming really difficult to understand the question... please provide solution
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 05 Dec 2018, 03:00
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Hello I tried doing the question but I am not able to get correct answer , my doubt is on the points P & Q are they both dividing the rectangle on same side i.e lengths/ breadth of the rectangle? without figure its becoming really difficult to understand the question... please provide solution
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Hi Archit3110

Yes, P and Q are points on the opposite sides of rectangle, ABCD. Since, AB and CD will be opposite to each other when you form a rectangle by marking the points, A, B, C and D either in clockwise or in anti-clockwise direction.

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P is a point on side AB of a rectangle ABCD, which divides AB ........ 05 Dec 2018, 03:02
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P is a point on side AB of a rectangle ABCD, which divides AB in the ratio 5: 3. Q is a point on CD, such that CQ: QD = 3: 1. If the area of rectangle ABCD is 480 sq. units, then what is the area of the quadrilateral ADQP?

    A. 105 sq. units
    B. 150 sq. units
    C. 175 sq. units
    D. 210 sq. units
    E. 270 sq. units

Show more
I think answer is D.
Please see the attached image for the solution.its tough to explain via typing.
I do not know what is the toughness level of this question but it did take me good amount of time to think this way.
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sol1.png [ 7.32 MiB | Viewed 8107 times ]

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P is a point on side AB of a rectangle ABCD, which divides AB ........ 05 Dec 2018, 03:25
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Archit3110


Hello I tried doing the question but I am not able to get correct answer , my doubt is on the points P & Q are they both dividing the rectangle on same side i.e lengths/ breadth of the rectangle? without figure its becoming really difficult to understand the question... please provide solution

Hi Archit3110

Yes, P and Q are points on the opposite sides of rectangle, ABCD. Since, AB and CD will be opposite to each other when you form a rectangle by marking the points, A, B, C and D either in clockwise or in anti-clockwise direction.

Regards,
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I was doing a calculation mistake... solution attached...

Posted from my mobile device
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P is a point on side AB of a rectangle ABCD, which divides AB ........ Updated on: 10 Dec 2018, 02:19
Originally posted by EgmatQuantExpert on 10 Dec 2018, 02:00.
Last edited by EgmatQuantExpert on 10 Dec 2018, 02:19, edited 3 times in total.
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Solution


Given:
    • P is a point on side AB of rectangle ABCD
      o P divides AB in the ratio 5: 3

    • Q is a point on side CD of rectangle ABCD
      o Q divides CD in the ratio 3: 1

    • The area of triangle ABCD = 480 sq. units

To find:
    • The area of quadrilateral ADQP

Approach and Working:



Let us assume that the length of AB = CD = x units, and length of BC = DA = h units
    • This implies,
      o Length of AP = \(\frac{5x}{(5 + 3)} = \frac{5x}{8}\)
      o Length of PB = \(\frac{3x}{(5 + 3)} = \frac{3x}{8}\)
      o Length of CQ = \(\frac{3x}{(1 + 3)} = \frac{3x}{4}\)
      o Length of QD = \(\frac{x}{(1 + 3)} = \frac{x}{4}\)

Area of quadrilateral, ADQP =\(\frac{1}{2} * h * (AP + QD) = \frac{1}{2} * h * (\frac{5x}{8} + \frac{x}{4}) = (\frac{7}{16}) * x * h\)
    o We are given that area of rectangle ABCD = 480 = AB * BC = x * h

Therefore, area of quadrilateral ADQP = \((\frac{7}{16}) * 480 = 210\) sq. units

Hence the correct answer is Option D.

Answer: D

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P is a point on side AB of a rectangle ABCD, which divides AB ........ 10 Dec 2018, 02:10
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Solution


Given:

We are given that,
    • AB and CD are two parallel chords of a circle
    • O is the center of the circle
    • AB = 12 and CD = 6
    • Diameter of the circle = 6√5

To find:
    • The distance between the two chords, AB and CD

Approach and Working:

From the above figure, we can infer that we need to find the value of EF

In triangle, OAE, we know that,
    • \(AE = \frac{AB}{2} = \frac{12}{2} = 6\)
    • OA = radius of the circle =\(\frac{6√5}{2} = 3√5\)
    • \(∠OEA = 90^o\)

So, we can write, \(OA^2 = OE^2 + AE^2\)
    • Implies, \((3√5)^2 = OE^2 + 6^2\)
    • \(OE^2 = 45 – 36 = 9\)
    • Thus, OE = √9 = 3

Similarly, in triangle DOF, we ca say that
    • \(OD^2 = OF^2 + FD^2\)
      o \((3√5)^2 = OF^2 + (\frac{6}{2})^2\)
      o \(OF^2 = 45 – 9 = 36\)

    • Thus, OF = √36 = 6

Therefore, EF = OF = OE = 6 – 3 = 3

Hence the correct answer is Option B.

Answer: B

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i think you have misplaced this solution here.please check
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 10 Dec 2018, 02:13
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vanam52923

i think you have misplaced this solution here.please check
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Hi vanam52923,

Yeah. Thanks for letting us know.
We have noticed it and changed the solution.

Regards,
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 01 Feb 2020, 15:17
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There's another easier way. Since the area of the whole rectangle is 480, let AB = DC = 80 (length of rectangle) and BC = AD = 6 (height).

AP:PB = 5:3. hence AP is (5/8)*80 = 50. same for DQ:QC = 1:3. DQ = (1/4)*80 = 20.

Area of ADQP (trapezoid) is (b+B)*h/2=(50+20)*6/3=70*3 = 210.

Hence D.
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 01 Feb 2020, 17:54
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Fastest way to do this is to recognize that the sides whos ratios are given are of the same part of the rectangle
5:3
3:1

Set side AB and DC length equal to 8
5x+1x = 8
x=1
AP=5*1 = 5
PB=3*1 = 3

3x+1x = 8
x=2
DQ = 1*2=2
QC = 3*2 = 6

Solve for height (or missing side of rectangle)
480 = 8*y
60 = y

solve the trapezoid
[(AP+DQ)/2]*h
[(5+2)/2] * 60
7*30
210
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 08 Mar 2020, 04:58
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Solution


Given:
    • P is a point on side AB of rectangle ABCD
      o P divides AB in the ratio 5: 3

    • Q is a point on side CD of rectangle ABCD
      o Q divides CD in the ratio 3: 1

    • The area of triangle ABCD = 480 sq. units

To find:
    • The area of quadrilateral ADQP

Approach and Working:



Let us assume that the length of AB = CD = x units, and length of BC = DA = h units
    • This implies,
      o Length of AP = \(\frac{5x}{(5 + 3)} = \frac{5x}{8}\)
      o Length of PB = \(\frac{3x}{(5 + 3)} = \frac{3x}{8}\)
      o Length of CQ = \(\frac{3x}{(1 + 3)} = \frac{3x}{4}\)
      o Length of QD = \(\frac{x}{(1 + 3)} = \frac{x}{4}\)

Area of quadrilateral, ADQP =\(\frac{1}{2} * h * (AP + QD) = \frac{1}{2} * h * (\frac{5x}{8} + \frac{x}{4}) = (\frac{7}{16}) * x * h\)
    o We are given that area of rectangle ABCD = 480 = AB * BC = x * h

Therefore, area of quadrilateral ADQP = \((\frac{7}{16}) * 480 = 210\) sq. units

Hence the correct answer is Option D.

Answer: D

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EgmatQuantExpert,

It appears that the image of the rectangle is misleading. CQ:QD is not appearing in the ration of 3:1.

Thank you.
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P is a point on side AB of a rectangle ABCD, which divides AB ........ 07 Jan 2021, 08:52
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In the figure we can see that : 4y = 8x. Therefore, y = 2x.

We need area of the two red areas combine. This can be calculated as :

Area of rectangle + area of triangle = AD*2x + 0.5*3x*AD = 3.5 x * AD

Also, area of ABCD = 480 = 8x * AD. -------> x * AD = 60.


Putting this value of x*AD in above figure we get : 3.5 * 60 = 210.


Kudos if helps :)

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P is a point on side AB of a rectangle ABCD, which divides AB ........ 14 Dec 2022, 04:49
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