gmatt1476
A bank account earned 2% annual interest, compounded daily, for as long as the balance was under $1,000, starting when the account was opened. Once the balance reached $1,000, the account earned 2.5% annual interest, compounded daily until the account was closed. No deposits or withdrawals were made. Was the total amount of interest earned at the 2% rate greater than the total amount earned at the 2.5% rate?
(1) The account earned exactly $25 in interest at the 2.5% rate.
(2) The account was open for exactly three years.
DS29931.01
The question is asking if the Interest earned at 2% > than the Interest earned at 2.5%
Let's say that:
Interest Earned at 2% = x
Interest Earned at 2.5 = Y
Here's my approach, which requires little math and more reasoning/logic:
1.) Interested Earned at 2.5% = $25
If the initial investment is $1, we would know that the interested earned from 2% would be greater than Interest earned from 2.5% ($25) X>Y
If the initial investment is $999, we would know that the interest earned from 2% would be smaller than the Interest earned from 2.5% ($25) Y>X
Insufficient2.) Time = 3 years
We don't know the starting values, if the initial investment is $1, in three years X>Y. If the initial investment is $999, then Y>X.
Insufficient1) + 2)
We know that time is 3 years, and that the interest earned at 2.5% is $25. This basically "locks" in the value of Y with a specific amount of time, so then we can directly solve for how much of the 3 years was the investment under $1000, and hence X.
Sufficient C is the Answer!
As per Statement 1, the account earned exactly $25 in interest at the 2.5% rate, how are we evaluating this value in context of 3 years? isn't this value primarily for 1 year? I think I am not able to understand this question.
Thanks.