Bunuel
Patrick is cleaning his house in anticipation of the arrival of guests. He needs to vacuum the floors, fold the laundry, and put away the dishes after the dishwasher completes its cycle. If the dishwasher is currently running and has 55 minutes remaining in its cycle, can Patrick complete all of the tasks before his guests arrive in exactly 1 hour?
(1) Vacuuming the floors and folding the laundry will take Patrick 36 minutes.
(2) Putting away the dishes will take Patrick 7 minutes.
Lets assign a name to each piece of task :
vacuum the floors = v, fold the laundry=f , put away the dishes=p & the dishwasher remaining cycle = r =55 mins
Patrick has 1 hr i.e., 60 mins in hand.
According to the q-stem ,although v and f can be done parallel to r, p only can be done after r.
(1) Vacuuming the floors and folding the laundry will take Patrick 36 minutes
v+f= 36 ...as 36<55 , these two will be done before guests arrive. thus time required for Patrick is r+p=55+p as p is not known ......
Insufficient.(2) Putting away the dishes will take Patrick 7 minutes.
p can only be done after r, thus if p=7, p+r=62>60 ... Hence Patrick cannot complete everything in 1hr...................
Sufficient.Hence I would go for
option B.