Game wrote:

Patrick purchased 80 pencils and sold them at a loss equal to the selling price of 20 pencils. The cost of 80 pencils is how many times the selling price of 80 pencils?

(A) 0.75

(B) 0.8

(C) 1

(D) 1.2

(E) 1.25

Source: Math bible Nova

Since the two blue values above are equal, the given question stem is the same as the following:

The cost of EACH PENCIL is how many times the selling price of EACH PENCIL?

Let the selling price of each pencil = $1.

Thus, the selling price of 80 pencils = $80.

Since Patrick's loss is equal to the selling price of 20 pencils, we get:

Loss = 20*1 = 20.

Since the 80 pencils are sold for $80 at a loss of $20, Patrick's cost for the 80 pencils must be $100.

Since 80 pencils have a total cost of $100, the cost per pencil \(= \frac{100}{80} = \frac{5}{4} = 1.25\).

Resulting ratio:

\(\frac{cost-per-pencil}{selling-price-per-pencil} = \frac{1.25}{1} = 1.25\).

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