Game wrote:
Patrick purchased 80 pencils and sold them at a loss equal to the selling price of 20 pencils. The cost of 80 pencils is how many times the selling price of 80 pencils?
(A) 0.75
(B) 0.8
(C) 1
(D) 1.2
(E) 1.25
Source: Math bible Nova
Since the two blue values above are equal, the given question stem is the same as the following:
The cost of EACH PENCIL is how many times the selling price of EACH PENCIL?
Let the selling price of each pencil = $1.
Thus, the selling price of 80 pencils = $80.
Since Patrick's loss is equal to the selling price of 20 pencils, we get:
Loss = 20*1 = 20.
Since the 80 pencils are sold for $80 at a loss of $20, Patrick's cost for the 80 pencils must be $100.
Since 80 pencils have a total cost of $100, the cost per pencil \(= \frac{100}{80} = \frac{5}{4} = 1.25\).
Resulting ratio:
\(\frac{cost-per-pencil}{selling-price-per-pencil} = \frac{1.25}{1} = 1.25\).
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