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17 Aug 2006, 17:19
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hi all
for the below Q i had 2 answers can someone explain why its counting andn ot permutation.
A car plate needs to be assigned 6 numbers ( 0-9) or alphabets 26 letters how many unique ways are possible
i used permutation formulas total available numbers are 10 + 26 = 36
so u need to get 6 so i went with 36P6
the answer is 36^6 thats 36 * 36 * 36 * 36 *36 * 36
my Q is whats wrong with 36P6
thanks
for the below Q i had 2 answers can someone explain why its counting andn ot permutation.
A car plate needs to be assigned 6 numbers ( 0-9) or alphabets 26 letters how many unique ways are possible
i used permutation formulas total available numbers are 10 + 26 = 36
so u need to get 6 so i went with 36P6
the answer is 36^6 thats 36 * 36 * 36 * 36 *36 * 36
my Q is whats wrong with 36P6
thanks
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17 Aug 2006, 17:55
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You need to figure out what 36P6 means. When you want to see a permutation of only 6 alphanumeric characters picked from 36 you will use 36P6.
The question asks how many different 6 letter/number alphanumeric codes can we generate.
The key is to break down the problem into simple terms.
Lets use an example.. ( a corny one maybe... )
Lets say I give you 36 movie DVDs....
If I ask you to pick one movie a day, in how many days will you start repeating the movies?
Answer : 36..
If you think about it, how many ways can you pick 1 item from 36 things... it is 36.
Now if I extend the example to alphanumeric codes, {A-B, 0-9}, you can pick the first of six numbers in 36 ways.
If you want to pick the second number then you can again pick it in 36 ways and so on...
Total number of ways = Number of ways you can pick first number x Number of ways you can pick second number x Number of ways you can pick third number x Number of ways you can pick fourth number x Number of ways you can pick fifth number xNumber of ways you can pick sixth number
= 36x36x36x36x36x36x36 = 36^6
Remember that this is true only if you can repeat the number/letter. If there is no repetition, then the answer is
36x35x34x33x32x31
Hope this helps.
The question asks how many different 6 letter/number alphanumeric codes can we generate.
The key is to break down the problem into simple terms.
Lets use an example.. ( a corny one maybe... )
Lets say I give you 36 movie DVDs....
If I ask you to pick one movie a day, in how many days will you start repeating the movies?
Answer : 36..
If you think about it, how many ways can you pick 1 item from 36 things... it is 36.
Now if I extend the example to alphanumeric codes, {A-B, 0-9}, you can pick the first of six numbers in 36 ways.
If you want to pick the second number then you can again pick it in 36 ways and so on...
Total number of ways = Number of ways you can pick first number x Number of ways you can pick second number x Number of ways you can pick third number x Number of ways you can pick fourth number x Number of ways you can pick fifth number xNumber of ways you can pick sixth number
= 36x36x36x36x36x36x36 = 36^6
Remember that this is true only if you can repeat the number/letter. If there is no repetition, then the answer is
36x35x34x33x32x31
Hope this helps.
17 Aug 2006, 21:51
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rxs0005
This is the case when no repitions are allowed.
rxs0005
This is the case when repitions are allowed.
rxs0005
Question doesn't say that repition is prohibited.
For example if I say how may combinations of two letters can be made using letters A,B and C.
Will you say 3P2 =6 :no
Correct is 3*3 = 9 :yes
But I say how may combinations of two letters can be made using letters A,B and C so that no bletter is repeated.
Then answer is 3P2 = 6
Permutation is nothing but selecting the items and then arranging.
Selecting = nCr and arranging = r!
so nPr = nCr * r!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
