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# PFA. I went for B.. probRedblue.JPG

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Manager
Joined: 09 Oct 2008
Posts: 93
PFA. I went for B.. probRedblue.JPG [#permalink]

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21 Oct 2008, 18:30
PFA.
I went for B..
Attachment:

probRedblue.JPG [ 28.54 KiB | Viewed 909 times ]

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Senior Manager
Joined: 04 Aug 2008
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21 Oct 2008, 18:52
I would say A

cant wait to see OA
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Joined: 29 Aug 2007
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21 Oct 2008, 21:22
spiridon wrote:
I would say A

cant wait to see OA

agree with A but what is your reasoning?
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Joined: 17 Jun 2008
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22 Oct 2008, 00:30
Question is essentially asking whether r > w.

From stmt1: r/(b+w) > w/(b+r)
(r+b+w)/(b+w) > (r+b+w)/(b+r)

or (b+w) < (b+r)
or, w < r and hence, sufficient.

Stmt2 does not help get this.
VP
Joined: 30 Jun 2008
Posts: 1018

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22 Oct 2008, 01:29
scthakur wrote:
Question is essentially asking whether r > w.

From stmt1: r/(b+w) > w/(b+r)
(r+b+w)/(b+w) > (r+b+w)/(b+r)

or (b+w) < (b+r)
or, w < r and hence, sufficient.

Stmt2 does not help get this.

Question is essentially asking whether r > w

how can we say this scthakur ?

the original question is r/(b+w) > w/(b+r)
how do we know that the denominator is not essential here ?

Thanks
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Joined: 17 Jun 2008
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22 Oct 2008, 02:00
amitdgr wrote:
Question is essentially asking whether r > w

how can we say this scthakur ?

the original question is r/(b+w) > w/(b+r)
how do we know that the denominator is not essential here ?

Thanks

The original question is r/(b+r+w) > w/(b+r+w) and since the denominator is the same, r > w.
VP
Joined: 30 Jun 2008
Posts: 1018

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22 Oct 2008, 02:09
scthakur wrote:
amitdgr wrote:
Question is essentially asking whether r > w

how can we say this scthakur ?

the original question is r/(b+w) > w/(b+r)
how do we know that the denominator is not essential here ?

Thanks

The original question is r/(b+r+w) > w/(b+r+w) and since the denominator is the same, r > w.

Ahh !! I guess I was sleeping when I read the explanation

I get it now scthakur thanks

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Re: GP2: Probabilty   [#permalink] 22 Oct 2008, 02:09
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# PFA. I went for B.. probRedblue.JPG

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