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27 Jul 2022, 19:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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64% (02:55) correct
36%
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Pipe A, pipe B and pipe C are used to fill a tank. The flow rate of pipe C is 25% less than pipe B. To fill the empty tank completely, Pipe A and Pipe B together take one third the time taken by Pipe C alone. If all three pipes can fill the tank in 15 hours, then find the time taken (in hours) by A alone to fill the tank completely.
A. 18
B. 27
C. 36
D. 45
E. 54
Source : Wizako
A. 18
B. 27
C. 36
D. 45
E. 54
Source : Wizako
27 Jul 2022, 20:07
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Suraj0184
A good rates question, Suraj0184
Making up a number for B's rate sure would make things easier...so let's do that!! This makes this question a Hidden Plug In.
B fills at a rate of 4 gallons per hour.
C fills 25% slower, so 3 gallons per hour.
A+B take 1/3 the time that C takes, so they fill at a combined rate of 3x C alone. C alone is 3, so A+B = 3(3) = 9. B = 4, so A = 5.
Okay, so we have A fills at 5 gallons per hour, B fills at 4 gallons per hour, and C fills at 3 gallons per hour. All three working together fill at 12 gallons per hour.
If all three can fill in 15 hours at a rate of 12 gallons per hour, the tank must hold 15*12 = 180 gallons.
How long does it take A to fill 180 gallons at a rate of 5 gallons per hour? 180/5 = 36.
Answer choice C.
ThatDudeKnowsHiddenPlugIn
27 Jul 2022, 21:41
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Pipe A, pipe B and pipe C are used to fill a tank. The flow rate of pipe C is 25% less than pipe B. To fill the empty tank completely, Pipe A and Pipe B together take one third the time taken by Pipe C alone. If all three pipes can fill the tank in 15 hours, then find the time taken (in hours) by A alone to fill the tank completely.
A. 18
B. 27
C. 36
D. 45
E. 54
The flow rate of pipe C is 25% less than pipe B (Given)
Let Pipe B's efficiency = 4 units/hour
then, Pipe C's efficiency = 3 units/hour
Pipe A's efficiency = x units/hour
Since, the Time taken is inversely proportional to Efficiency,
3* Time (A+B) = Time (C alone) (Given)
Hence, Efficiency (A+B) = 3 * Efficiency (C alone)
(4+x) = 3 * 3
x=5
Hence, Work = 15 days * (4+5+3) units/day = 180 units
So, Time taken (by A alone) = 180/5 = 36 hours
A. 18
B. 27
C. 36
D. 45
E. 54
The flow rate of pipe C is 25% less than pipe B (Given)
Let Pipe B's efficiency = 4 units/hour
then, Pipe C's efficiency = 3 units/hour
Pipe A's efficiency = x units/hour
Since, the Time taken is inversely proportional to Efficiency,
3* Time (A+B) = Time (C alone) (Given)
Hence, Efficiency (A+B) = 3 * Efficiency (C alone)
(4+x) = 3 * 3
x=5
Hence, Work = 15 days * (4+5+3) units/day = 180 units
So, Time taken (by A alone) = 180/5 = 36 hours
