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njvenkatesh
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Please help GMATPrep 13 Jun 2006, 09:01
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Hi,

Can someone help me with this question.

Thanks in advance.



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Yurik79
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Please help GMATPrep 13 Jun 2006, 09:07
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it is simple the area of LMN=1/2*(12*12)=72
the area of PQR=1/2*(6*4)=12
LMN/PQR=72/12=1/6
C it is
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njvenkatesh
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Please help GMATPrep 13 Jun 2006, 09:11
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This is a GMATprep question and the answer given there is 1/9.

Don't know How 1/9 is the answer
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haas_mba07
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Please help GMATPrep 13 Jun 2006, 09:40
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1/9 is Correct...

Area PQR = (base x height)/2 = (4x4)/2 = 8

Area LMN - (base x height)/2 = (12x12)/2 = 72

Ratio = Area PQR/Area LMN = 8/72 = 1/9


njvenkatesh
This is a GMATprep question and the answer given there is 1/9.

Don't know How 1/9 is the answer
Show more
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haas_mba07
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Please help GMATPrep 13 Jun 2006, 09:42
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Yurik79
it is simple the area of LMN=1/2*(12*12)=72
the area of PQR=1/2*(6*4)=12
LMN/PQR=72/12=1/6
C it is
Show more



Shouldn't that be 1/2*(4*4)
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shobhitb
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Please help GMATPrep 13 Jun 2006, 09:42
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Yurik79
it is simple the area of LMN=1/2*(12*12)=72
the area of PQR=1/2*(4*4)=8
PQR/LMN=8/72=1/9
A it is
Show more


Correcting slight mistakes of Yurik
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haas_mba07
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Please help GMATPrep 13 Jun 2006, 10:45
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:)

shobhitb
Yurik79
it is simple the area of LMN=1/2*(12*12)=72
the area of PQR=1/2*(4*4)=8
PQR/LMN=8/72=1/9
A it is

Correcting slight mistakes of Yurik
Show more
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Yurik79
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Please help GMATPrep 13 Jun 2006, 12:35
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haas_mba07
Yurik79
it is simple the area of LMN=1/2*(12*12)=72
the area of PQR=1/2*(6*4)=12
LMN/PQR=72/12=1/6
C it is


Shouldn't that be 1/2*(4*4)
Show more

))agree my fault stupid mistake
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gidimba
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Please help GMATPrep 13 Jun 2006, 13:35
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1/9

Small triangle = 0.5[4*4] = 8
Large triangle = 0.5 [12][12] = 72

8/72 = 1/9
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jaynayak
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Please help GMATPrep 13 Jun 2006, 22:22
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Height of PQR = 4 (y co-ordinate is 4)
Base of PQR = 4 (x2-x1)

Area of PQR = 4*4*1/2

Height of LMN = 12 (y co-ordinate is 12)
Base of LMN = 12 (x2-x1)

Area of LMN = 12*12*1/2

Fraction = (4*4*1/2)/(12*12*1/2)

= 1/9



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!