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Intern
Joined: 14 Jan 2016
Posts: 2

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02 Dec 2017, 13:38
Please how can this exponential equation be solved 2^3 + 3^2+ 4^5+5^3?
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Joined: 17 Jul 2014
Posts: 2657
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
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03 Dec 2017, 21:21
1
uyplus wrote:
Please how can this exponential equation be solved 2^3 + 3^2+ 4^5+5^3?

the only option here is to raise everything to the specified power. the only one you can combine is 4^5 which is 2^10
2^3 = 8
3^2 = 9
4^5 = 1024
5^3 = 125

total: 1,166.

sometimes it is easier if you can find a common factor.
for example, have we had 2^3 + 3^2 + 4^5 + 9^3, we could have rewritten everything as:
2^3 + 3^2 + 2^10 + 3^6
then we would bring a common factor in the front:
2^3 * (1 + 2^7) + 3^2(1+3^4)

most of the times, the answer to the question would be in this format too, so that you would not have to calculate everything.
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Joined: 30 Jan 2016
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Location: United States (MA)

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07 Dec 2017, 09:30
You can find more on exponents here:
https://gmatclub.com/forum/exponents-an ... 74993.html
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