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In What Ratio must a shopkeeper mix two type of rice worth Rs 50/- per Kg and Rs 58/- per kg so that by selling the mixture of Rs 58.30/- per kg and he may gain 10%?
A) 3 :2
B) 5:2
C) 4:3
D) 5: 3
Selling Price of 1 kg of rice of the mixture = 58,350/-
Gain = 10%
Cost Price of 1 kg of the mixture = \(100\times58.35\times110\) = Rs 53/-
By the rule of alligation:
C.P.M.1 = (Cost Price of First rice) = Rs 50/-
C.P.M 2 = (Cost Price of Second Rice) = Rs 58/-
M.P = (Mean Price of both material) = Rs 53.00/-
So,
(C.P.M - M.P) : ( C.P.M.2 - M.P.)
= (50 - 53): (58-53)
= 5 : 3
Why 5: 3 instead of 3:5?
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In What Ratio must a shopkeeper mix two type of rice worth Rs 50/- per Kg and Rs 58/- per kg so that by selling the mixture of Rs 58.30/- per kg and he may gain 10%?
A) 3 :2
B) 5:2
C) 4:3
D) 5: 3
Selling Price of 1 kg of rice of the mixture = 58,350/-
Gain = 10%
Cost Price of 1 kg of the mixture = \(100\times58.35\times110\) = Rs 53/-
By the rule of alligation:
C.P.M.1 = (Cost Price of First rice) = Rs 50/-
C.P.M 2 = (Cost Price of Second Rice) = Rs 58/-
M.P = (Mean Price of both material) = Rs 53.00/-
So,
(C.P.M - M.P) : ( C.P.M.2 - M.P.)
= (50 - 53): (58-53)
= 5 : 3
Why 5: 3 instead of 3:5?
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