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Intern
Joined: 12 Apr 2018
Posts: 4

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12 Apr 2018, 23:57
00:00

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Question Stats:

50% (03:06) correct 50% (00:04) wrong based on 2 sessions

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In What Ratio must a shopkeeper mix two type of rice worth Rs 50/- per Kg and Rs 58/- per kg so that by selling the mixture of Rs 58.30/- per kg and he may gain 10%?

A) 3 :2

B) 5:2

C) 4:3

D) 5: 3

Selling Price of 1 kg of rice of the mixture = 58,350/-

Gain = 10%

Cost Price of 1 kg of the mixture = $$100\times58.35\times110$$ = Rs 53/-

By the rule of alligation:

C.P.M.1 = (Cost Price of First rice) = Rs 50/-

C.P.M 2 = (Cost Price of Second Rice) = Rs 58/-

M.P = (Mean Price of both material) = Rs 53.00/-

So,

(C.P.M - M.P) : ( C.P.M.2 - M.P.)

= (50 - 53): (58-53)

= 5 : 3

Why 5: 3 instead of 3:5?
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 44599

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13 Apr 2018, 00:05
kingston123 wrote:
In What Ratio must a shopkeeper mix two type of rice worth Rs 50/- per Kg and Rs 58/- per kg so that by selling the mixture of Rs 58.30/- per kg and he may gain 10%?

A) 3 :2

B) 5:2

C) 4:3

D) 5: 3

Selling Price of 1 kg of rice of the mixture = 58,350/-

Gain = 10%

Cost Price of 1 kg of the mixture = $$100\times58.35\times110$$ = Rs 53/-

By the rule of alligation:

C.P.M.1 = (Cost Price of First rice) = Rs 50/-

C.P.M 2 = (Cost Price of Second Rice) = Rs 58/-

M.P = (Mean Price of both material) = Rs 53.00/-

So,

(C.P.M - M.P) : ( C.P.M.2 - M.P.)

= (50 - 53): (58-53)

= 5 : 3

Why 5: 3 instead of 3:5?

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