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Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t

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Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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New post 14 Mar 2019, 10:38
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Question Stats:

51% (01:14) correct 49% (01:15) wrong based on 53 sessions

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Point (A,B) is randomly selected inside of circle \(x^2+y^2\)=1. What is the probability that A>B>0?

A) \(1/4\)
B) \(1/8\)
C) \(1/6\)
D) \(1/2\)
E) \(1\)
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Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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New post 19 Mar 2019, 11:30
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle \(x^2+y^2\)=1. What is the probability that A>B>0?

A) \(1/4\)
B) \(1/8\)
C) \(1/6\)
D) \(1/2\)
E) \(1\)


area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
1/4 ; should be answer
PriyankaPalit7
is given answer option correct?
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Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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New post 19 Mar 2019, 13:09
As per the attached picture answer should be 1/8
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GMAT 3: 730 Q50 V40
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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New post 20 Mar 2019, 04:10
Archit3110 wrote:
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle \(x^2+y^2\)=1. What is the probability that A>B>0?

A) \(1/4\)
B) \(1/8\)
C) \(1/6\)
D) \(1/2\)
E) \(1\)


area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
1/4 ; should be answer
PriyankaPalit7
is given answer option correct?


Quadrant i would have A and B > 0. ie. positive values for A and B.
But only half of quadrant 1 would have A > B. SO the correct answer is B 1/8.
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Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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New post 16 Sep 2019, 10:02
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle \(x^2+y^2\)=1. What is the probability that A>B>0?

A) \(1/4\)
B) \(1/8\)
C) \(1/6\)
D) \(1/2\)
E) \(1\)


You are also including the probability of the point lying on y=x and y=0 as you are considering those points also in the area, which should not be the case as a cannot be equal to b and y cannot be equal to 0
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Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t   [#permalink] 16 Sep 2019, 10:02
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