GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 14 Dec 2019, 10:50

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t

Author Message
TAGS:

Hide Tags

Manager
Joined: 28 May 2018
Posts: 150
Location: India
Schools: ISB '21 (A)
GMAT 1: 640 Q45 V35
GMAT 2: 670 Q45 V37
GMAT 3: 730 Q50 V40
Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

Show Tags

14 Mar 2019, 10:38
6
00:00

Difficulty:

55% (hard)

Question Stats:

51% (01:14) correct 49% (01:15) wrong based on 53 sessions

HideShow timer Statistics

Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$
GMAT Club Legend
Joined: 18 Aug 2017
Posts: 5483
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

Show Tags

19 Mar 2019, 11:30
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$

area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
PriyankaPalit7
Intern
Joined: 11 May 2018
Posts: 24
Location: India
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

Show Tags

19 Mar 2019, 13:09
As per the attached picture answer should be 1/8
Attachments

Untitled.png [ 18.18 KiB | Viewed 563 times ]

Manager
Joined: 28 May 2018
Posts: 150
Location: India
Schools: ISB '21 (A)
GMAT 1: 640 Q45 V35
GMAT 2: 670 Q45 V37
GMAT 3: 730 Q50 V40
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

Show Tags

20 Mar 2019, 04:10
Archit3110 wrote:
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$

area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
PriyankaPalit7

Quadrant i would have A and B > 0. ie. positive values for A and B.
But only half of quadrant 1 would have A > B. SO the correct answer is B 1/8.
Intern
Joined: 20 Jan 2018
Posts: 1
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

Show Tags

16 Sep 2019, 10:02
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$

You are also including the probability of the point lying on y=x and y=0 as you are considering those points also in the area, which should not be the case as a cannot be equal to b and y cannot be equal to 0
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t   [#permalink] 16 Sep 2019, 10:02
Display posts from previous: Sort by