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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t

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Manager  P
Joined: 28 May 2018
Posts: 150
Location: India
Schools: ISB '21 (A)
GMAT 1: 640 Q45 V35 GMAT 2: 670 Q45 V37 GMAT 3: 730 Q50 V40 Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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6 00:00

Difficulty:   55% (hard)

Question Stats: 51% (01:14) correct 49% (01:15) wrong based on 53 sessions

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Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$
GMAT Club Legend  V
Joined: 18 Aug 2017
Posts: 5483
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$

area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
PriyankaPalit7
Intern  B
Joined: 11 May 2018
Posts: 24
Location: India
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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As per the attached picture answer should be 1/8
Attachments Untitled.png [ 18.18 KiB | Viewed 563 times ]

Manager  P
Joined: 28 May 2018
Posts: 150
Location: India
Schools: ISB '21 (A)
GMAT 1: 640 Q45 V35 GMAT 2: 670 Q45 V37 GMAT 3: 730 Q50 V40 Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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Archit3110 wrote:
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$

area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
PriyankaPalit7

Quadrant i would have A and B > 0. ie. positive values for A and B.
But only half of quadrant 1 would have A > B. SO the correct answer is B 1/8.
Intern  B
Joined: 20 Jan 2018
Posts: 1
Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  [#permalink]

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PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle $$x^2+y^2$$=1. What is the probability that A>B>0?

A) $$1/4$$
B) $$1/8$$
C) $$1/6$$
D) $$1/2$$
E) $$1$$

You are also including the probability of the point lying on y=x and y=0 as you are considering those points also in the area, which should not be the case as a cannot be equal to b and y cannot be equal to 0 Re: Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t   [#permalink] 16 Sep 2019, 10:02
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# Point (A,B) is randomly selected inside of circle x^2+y^2=1. What is t  