Archit3110 wrote:
PriyankaPalit7 wrote:
Point (A,B) is randomly selected inside of circle \(x^2+y^2\)=1. What is the probability that A>B>0?
A) \(1/4\)
B) \(1/8\)
C) \(1/6\)
D) \(1/2\)
E) \(1\)
area of circle = pi * r^2
r=1 so area of pi
so only at 1st quadrant a>b>0 would be valid
1/4 ; should be answer
PriyankaPalit7is given answer option correct?
Quadrant i would have A and B > 0. ie. positive values for A and B.
But only half of quadrant 1 would have A > B. SO the correct answer is B 1/8.
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54% (01:15) correct 
