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# Point A is 10 miles West of Point B. Point B is 30 miles North of Poin

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Math Expert
Joined: 02 Sep 2009
Posts: 59589
Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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Updated on: 22 Jul 2019, 06:12
00:00

Difficulty:

15% (low)

Question Stats:

89% (01:58) correct 11% (02:42) wrong based on 27 sessions

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Point A is 10 miles West of Point B. Point B is 30 miles North of Point C. Point C is 20 miles East of Point D. What is the distance between points A and D?

(A) $$10 \sqrt{10}$$ miles

(B) $$10 \sqrt{20}$$ miles

(C) $$20 \sqrt{10}$$ miles

(D) $$30 \sqrt{10}$$ miles

(E) $$30 \sqrt{20}$$ miles

Source: Nova GMAT
Difficulty Level: 550

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Originally posted by Bunuel on 02 Apr 2019, 23:48.
Last edited by SajjadAhmad on 22 Jul 2019, 06:12, edited 1 time in total.
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Re: Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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03 Apr 2019, 07:59
Bunuel wrote:
Point A is 10 miles West of Point B. Point B is 30 miles North of Point C. Point C is 20 miles East of Point D. What is the distance between points A and D?

(A) $$10 \sqrt{10}$$ miles

(B) $$10 \sqrt{20}$$ miles

(C) $$20 \sqrt{10}$$ miles

(D) $$30 \sqrt{10}$$ miles

(E) $$30 \sqrt{20}$$ miles

draw a figure we get a rectangle and triangle
AD = √900+100 ; √1000 ; 10√10
IMO A
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Joined: 16 Jan 2019
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Re: Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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03 Apr 2019, 13:05
1
Hi there, can someone please explain what equation to use?

I drew out the points and then drew a triangle for points ADC - I got the length of DC as 20 and AC as 20... to find AD I did the pythagorean theorem to find the distance - hypotenuse. Was my logic in finding the distance incorrect? How do I know what to use to solve this? Thank you in advance!
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Re: Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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06 Apr 2019, 13:00
jojo95 wrote:
Hi there, can someone please explain what equation to use?

I drew out the points and then drew a triangle for points ADC - I got the length of DC as 20 and AC as 20... to find AD I did the pythagorean theorem to find the distance - hypotenuse. Was my logic in finding the distance incorrect? How do I know what to use to solve this? Thank you in advance!

Attachment:

Gmat Club question.jpg [ 15.46 KiB | Viewed 728 times ]

Hi jojo95,
You most probably drew the figure wrong, look at the figure above.Also look the Directions on the Right
In $$\Delta$$ ADE we can use Pythagoras theorem and find AD
$$AD^2 =30^2+10^2\\ AD^2 =900+100\\ AD=\sqrt{1000} \rightarrow 10\sqrt{10}$$

Hope this helps.
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- Stne
Re: Point A is 10 miles West of Point B. Point B is 30 miles North of Poin   [#permalink] 06 Apr 2019, 13:00
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