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Point A is 10 miles West of Point B. Point B is 30 miles North of Poin

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Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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New post 02 Apr 2019, 23:48
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Point A is 10 miles West of Point B. Point B is 30 miles North of Point C. Point C is 20 miles East of Point D. What is the distance between points A and D?


(A) \(10 \sqrt{10}\) miles

(B) \(10 \sqrt{20}\) miles

(C) \(20 \sqrt{10}\) miles

(D) \(30 \sqrt{10}\) miles

(E) \(30 \sqrt{20}\) miles

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Re: Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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New post 03 Apr 2019, 07:59
Bunuel wrote:
Point A is 10 miles West of Point B. Point B is 30 miles North of Point C. Point C is 20 miles East of Point D. What is the distance between points A and D?


(A) \(10 \sqrt{10}\) miles

(B) \(10 \sqrt{20}\) miles

(C) \(20 \sqrt{10}\) miles

(D) \(30 \sqrt{10}\) miles

(E) \(30 \sqrt{20}\) miles


draw a figure we get a rectangle and triangle
AD = √900+100 ; √1000 ; 10√10
IMO A
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Re: Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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New post 03 Apr 2019, 13:05
Hi there, can someone please explain what equation to use?

I drew out the points and then drew a triangle for points ADC - I got the length of DC as 20 and AC as 20... to find AD I did the pythagorean theorem to find the distance - hypotenuse. Was my logic in finding the distance incorrect? How do I know what to use to solve this? Thank you in advance!
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Point A is 10 miles West of Point B. Point B is 30 miles North of Poin  [#permalink]

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New post 06 Apr 2019, 13:00
jojo95 wrote:
Hi there, can someone please explain what equation to use?

I drew out the points and then drew a triangle for points ADC - I got the length of DC as 20 and AC as 20... to find AD I did the pythagorean theorem to find the distance - hypotenuse. Was my logic in finding the distance incorrect? How do I know what to use to solve this? Thank you in advance!

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Hi jojo95,
You most probably drew the figure wrong, look at the figure above.Also look the Directions on the Right
In \(\Delta\) ADE we can use Pythagoras theorem and find AD
\(AD^2 =30^2+10^2\\
AD^2 =900+100\\
AD=\sqrt{1000} \rightarrow 10\sqrt{10}\)

Hope this helps.
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Point A is 10 miles West of Point B. Point B is 30 miles North of Poin   [#permalink] 06 Apr 2019, 13:00
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