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Difficulty:
55%
(hard)
Question Stats:
60% (01:54) correct
40%
(01:50)
wrong
based on 357
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Point (r,s) lies on the line L. Is the line’s intercept with axis-x greater than r?
(1) L has a negative slope.
(2) s<0
(1) L has a negative slope.
(2) s<0
01 Nov 2010, 05:16
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This question can be easily solved if you understand the concept of slope and x intercept.
Negative slope means that the line is going down from left to right.
x intercept is the point at which the line crosses the x axis.
You know that (r, s) lies on the line and want to find if x intercept is greater than r.
Statement 1: If line has negative slope, (r, s) could still be above x axis or below x axis on the line. If it is above x axis, r < x intercept. If it is below x axis, r > x intercept. See the 1st diagram below.
Statement 2: If s < 0, it means the point (r, s) lies below x axis (s is the y co-ordinate and it is negative below x axis). But if the slope of the line is positive, r < x intercept and if the slope is negative, r > x intercept. See the 2nd diagram below.
Ques.jpg [ 17.47 KiB | Viewed 9830 times ]
When both the statements are combined, slope of line is negative and (r, s) lies below the x axis, then (r, s) has to lie to the right of the x intercept. Hence r will always be greater than x intercept.
Ques1.jpg [ 9.6 KiB | Viewed 9777 times ]
So we can conclusively answer the question with 'No. Line's x intercept is not greater than r.' Answer (C).
Negative slope means that the line is going down from left to right.
x intercept is the point at which the line crosses the x axis.
You know that (r, s) lies on the line and want to find if x intercept is greater than r.
Statement 1: If line has negative slope, (r, s) could still be above x axis or below x axis on the line. If it is above x axis, r < x intercept. If it is below x axis, r > x intercept. See the 1st diagram below.
Statement 2: If s < 0, it means the point (r, s) lies below x axis (s is the y co-ordinate and it is negative below x axis). But if the slope of the line is positive, r < x intercept and if the slope is negative, r > x intercept. See the 2nd diagram below.
Attachment:
Ques.jpg [ 17.47 KiB | Viewed 9830 times ]
When both the statements are combined, slope of line is negative and (r, s) lies below the x axis, then (r, s) has to lie to the right of the x intercept. Hence r will always be greater than x intercept.
Attachment:
Ques1.jpg [ 9.6 KiB | Viewed 9777 times ]
So we can conclusively answer the question with 'No. Line's x intercept is not greater than r.' Answer (C).
20 May 2010, 01:27
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dimitri92
Equation of a line in point intercept form is \(y=mx+b\), where: \(m\) is the slope of the line; \(b\) is the y-intercept of the line (the value of \(y\) for \(x=0\)); \(x\) is the independent variable of the function \(y\).
Point (r,s) lies on the line L --> \(s=mr+b\).
Lines intercept with x-axis (x-intercept) is the value of \(x\) for \(y=0\) --> \(x=-\frac{b}{m}\).
Q: is \(-\frac{b}{m}>r\)? --> substitute \(b\) and simplify --> \(-\frac{s-mr}{m}>r\)? --> \(-\frac{s}{m}+r>r\)? --> \(\frac{s}{m}<0\)?
So the question became: is \(\frac{s}{m}<0\)? we need to know signs of \(s\) and \(m\).
(1) \(m<0\). No info about \(s\). Not sufficient.
(2) \(s<0\). No info about \(m\). Not sufficient.
(1)+(2) Sufficient.
Answer: C.
