Shreshtha55 wrote:
chetan2u can you please explain this?
Let join AB, and CO. Now, CO will bisect AB in two halves of 6/2 or 3..
Now since C is in the middle, the other thing will be that the chord AB and radius OC will be perpendicular to each other.
So, take triangle ADO with hypotenuse as 5 and one side as 3, so sides are 3:4:5, so OD = 4.
Now let us take triangle ADB, again a right angled triangle. BD=5-4=1, and AD = 3, so AC = \(\sqrt{1^2+3^2}=\sqrt{10}\).
Thank you for your solution,but some portions are not clear, can you check , in the last line did you mean triangle ADC rather than ADB also did you mean CD rather than BD,