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27 Mar 2019, 21:07
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
61% (02:09) correct
39%
(02:38)
wrong
based on 80
sessions
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Points A and B are on a circle of radius 5 and AB = 6. Point C is the midpoint of the minor arc AB. What is the length of the line segment AC?
(A) \(\sqrt{10}\)
(B) 7/2
(C) \(\sqrt{14}\)
(D) \(\sqrt{15}\)
(E) 4
(A) \(\sqrt{10}\)
(B) 7/2
(C) \(\sqrt{14}\)
(D) \(\sqrt{15}\)
(E) 4
27 Mar 2019, 22:22
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Let O be centre of the circle
As AB is the arc and it's midpoint is given as C. If we draw a perpendicular from to AB it will bisect the chord AB at D(assumed point) and meet C such that OC=5=OD+DC
NOW, TRIANGLE OAD is rt angled triangle
And we can find OD using Pythagoras OD=rt(5^2-3^2)=4
Similarly triangle ADC is also a rt angled triangle and we can find AC using Pythagoras, AC=rt(3^2+1^2)=rt10
Posted from my mobile device
As AB is the arc and it's midpoint is given as C. If we draw a perpendicular from to AB it will bisect the chord AB at D(assumed point) and meet C such that OC=5=OD+DC
NOW, TRIANGLE OAD is rt angled triangle
And we can find OD using Pythagoras OD=rt(5^2-3^2)=4
Similarly triangle ADC is also a rt angled triangle and we can find AC using Pythagoras, AC=rt(3^2+1^2)=rt10
Posted from my mobile device
28 Mar 2019, 03:29
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chetan2u can you please explain this?
