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# Positive integer n divisible by 4 and 21

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Joined: 08 Jul 2009
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Positive integer n divisible by 4 and 21 [#permalink]

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19 Jul 2009, 10:00
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This question and answer explanation is from a Manhattan GMAT practice test. I don't understand why they don't take into account the 7 as one of the prime factors. Can anyone explain this? Thanks for your help.

If positive integer n is divisible by both 4 and 21, then n must be divisible by which of the following?

8 - 2, 2, 2

12 - 2, 2, 3

18, 2, 3, 3

24 - 2, 2, 2, 3

48- , 2, 2, 2, 2,

If n is divisible by both 4 and 21, its prime factors include 2, 2, 3, and 7. Therefore, any integer that can be constructed as the product of these prime factors is also a factor of n. In this case, 12 is the only integer that can definitively be constructed from the prime factors of n, since 12 = 2 x 2 x 3.

The correct answer is B.

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Manager
Joined: 19 Jun 2009
Posts: 141

Kudos [?]: 18 [0], given: 21

Location: India
Concentration: Strategy, General Management
GMAT 1: 650 Q51 V27
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WE: Engineering (Computer Hardware)
Re: Positive integer n divisible by 4 and 21 [#permalink]

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19 Jul 2009, 11:08
You are confused.

Read the question again, carefully.

If you still don't get it, here it is -

Now, prime factors :

4= 2, 2.
21=3,7.

'n' is divisible by 4 & 21.
Consider, Y is divisor after dividing 'n' by 4 & 21.
Let's write 'n' as

n = 4 x 21 x Y = 2 x 2 x 3 x 7 x Y.

Now, question asks for a number that divides 'n'. If there is a number that divides 'n' for sure, it must not have any additional prime factors than (2,2,3,7). Consider the possibility that Y might even be 1, so we don't consider Y here.

All other options except '12'=2 x 2 x 3, have those additional prime factors.

This is complete logic. Quick way to solve the problem -

Divide 4 x 21 by each option given. The one which gives integer divisor, is your answer.
_________________

I am ready to fall, but not before I fly.

Kudos [?]: 18 [0], given: 21

Manager
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Re: Positive integer n divisible by 4 and 21 [#permalink]

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22 Jul 2009, 00:16
well explained alpeshvc.

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Manager
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Re: Positive integer n divisible by 4 and 21 [#permalink]

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23 Jul 2009, 04:31
1
KUDOS
In Other way, the first number,apart from 0, is LCM of 4 and 21. This is 84.
so out of the following only 12 divides it. Thanks.
nss123 wrote:
This question and answer explanation is from a Manhattan GMAT practice test. I don't understand why they don't take into account the 7 as one of the prime factors. Can anyone explain this? Thanks for your help.

If positive integer n is divisible by both 4 and 21, then n must be divisible by which of the following?

8 - 2, 2, 2

12 - 2, 2, 3

18, 2, 3, 3

24 - 2, 2, 2, 3

48- , 2, 2, 2, 2,

If n is divisible by both 4 and 21, its prime factors include 2, 2, 3, and 7. Therefore, any integer that can be constructed as the product of these prime factors is also a factor of n. In this case, 12 is the only integer that can definitively be constructed from the prime factors of n, since 12 = 2 x 2 x 3.

The correct answer is B.

Kudos [?]: 123 [1], given: 3

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Joined: 09 Sep 2013
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Re: Positive integer n divisible by 4 and 21 [#permalink]

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26 Dec 2016, 06:25
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Re: Positive integer n divisible by 4 and 21   [#permalink] 26 Dec 2016, 06:25
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# Positive integer n divisible by 4 and 21

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