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24 Mar 2016, 02:56
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If positive integer n is divisible by both 4 and 21, then n must be divisible by which of the following?
A. 8
B. 12
C. 18
D. 24
E. 48
A. 8
B. 12
C. 18
D. 24
E. 48
24 Mar 2016, 05:23
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A number divisible by both 4 & 21 is 84 which s divisible by 12.
IMO : Answer B 12
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IMO : Answer B 12
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31 Mar 2016, 03:00
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If positive integer n is divisible by both 4 and 21, then n must be divisible by which of the following?
Let me take somewhat basic approach
X is divisible by 4
X = 4x = factors {2,2}
X is divisible by 21
X= 7x = factors {3,7}
As all factors in this case are exclusive and nothing in common between
So minimum set of factors is { 2,2,3,7 }
This number thus must be divisible by 4 (given), 21 (given), {2,3} = 6 , {2,7}= 14 , {3,7} = 21 , {2,2,3} = 12 , {2,2,7} = 28 , {2,3,7} = 42 , {2,2,3,7}= 8
As per given options 12 seems right
Let me take somewhat basic approach
X is divisible by 4
X = 4x = factors {2,2}
X is divisible by 21
X= 7x = factors {3,7}
As all factors in this case are exclusive and nothing in common between
So minimum set of factors is { 2,2,3,7 }
This number thus must be divisible by 4 (given), 21 (given), {2,3} = 6 , {2,7}= 14 , {3,7} = 21 , {2,2,3} = 12 , {2,2,7} = 28 , {2,3,7} = 42 , {2,2,3,7}= 8
As per given options 12 seems right
