Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 2808:30 AM PDT
-09:30 AM PDT
Are you constantly rereading GMAT RC passages but still struggling to understand them? Most students think rereading improves accuracy — but in reality, it usually signals a flawed reading strategy.
May 2110:00 AM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.- May 27
08:30 AM PDT
-09:30 AM PDT
Next - GMAT Ninja CR series, we tackle a very specific flavor of Critical Reasoning: Plans & Goals questions. The GMAT loves to present a scenario where a company, government, or individual proposes a seemingly brilliant plan to achieve a specific goal. - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Updated on: 26 Oct 2017, 06:46
Originally posted by papillon86 on 08 Nov 2009, 14:11.
Last edited by Bunuel on 26 Oct 2017, 06:46, edited 3 times in total.
Last edited by Bunuel on 26 Oct 2017, 06:46, edited 3 times in total.
Edited the question and added the OA
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
61% (01:57) correct
39%
(02:04)
wrong
based on 1605
sessions
History
Date
Time
Result
Not Attempted Yet
In the x-y plane, the area of the region bounded by the graph of |x + y| + |x - y| = 4 is
A. 8
B. 12
C. 16
D. 20
E. 24
A. 8
B. 12
C. 16
D. 20
E. 24
08 Nov 2009, 14:34
Kudos
Bookmarks
papillon86
OK, there can be 4 cases:
|x+y| + |x-y| = 4
A. x+y+x-y = 4 --> x=2
B. x+y-x+y = 4 --> y=2
C. -x-y +x-y= 4 --> y=-2
D. -x-y-x+y=4 --> x=-2
The area bounded by 4 graphs x=2, x=-2, y=2, y=-2 will be square with the side of 4 so the area will be 4*4=16.
Attachment:
MSP17971c13h40gd024h6g10000466ge1e9df941i96.gif [ 1.86 KiB | Viewed 53152 times ]
Answer: C
08 Nov 2009, 17:41
Kudos
Bookmarks
srini123
I think this one is different.
\(|\frac{x}{2}| + |\frac{y}{2}| = 5\)
After solving you'll get equation of four lines:
\(y=-10-x\)
\(y=10+x\)
\(y=10-x\)
\(y=x-10\)
These four lines will also make a square, BUT in this case the diagonal will be 20 so the \(Area=\frac{20*20}{2}=200\). Or the \(Side= \sqrt{200}\), area=200.
If you draw these four lines you'll see that the figure (square) which is bounded by them is turned by 90 degrees and has a center at the origin. So the side will not be 20.
Also you made a mistake in solving equation. The red part is not correct. You should have the equations written above.
In our original question when we were solving the equation |x+y| + |x-y| = 4 each time x or y were cancelling out so we get equations of a type x=some value twice and y=some value twice. And these equations give the lines which are parallel to the Y or X axis respectively so the figure bounded by them is a "horizontal" square (in your question it's "diagonal" square).
Hope it's clear.
