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I could not load the Venn Diagram, Please try to visualize it. ( The diagram is posted below)

a, b, and c one product each.

x, y, and z two products each.

d all three products.


a + b + c + d + x + y + z = 100
If you assume there is no one who uses two products each, then x = y = z = 0.
So, a + b + c + d = 100 ----------------(1)
a + d = 80 ------------------------------(2)
b + d = 75 ------------------------------(3)
c + d = 55 ------------------------------(4)

From 2, 3, and 4,
a + b + c + 3d = 210 ----------------(5)
a + b + c + d + 2d = 210

From 1 and 5,
100 + 2d = 210
d = 55 --------------Maximum.

If you assume there is no one who uses one product each, then a = b = c = 0.
So, d + x + y + z = 100 ----------------(6)
x + y + d = 80 ------------------------------(7)
x + z + d = 75 ------------------------------(8)
y + z + d = 55 ------------------------------(9)

From 7, 8, and 9,
2x + 2y + 2z + 3d = 2(x + y + z + d ) + d = 210 ----------------(10)

From 6 and 10,
2(100) + d = 210
d = 10 --------------Minimum.

So Maximum – minimum = 55 – 10 = 45.
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The most they could overlap is 55 of course. And for the least, I think it's best to draw lines or venn diagrams where you make the minimum amount of overlap of all 3:

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Hope this helps
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In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player.

If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x – y is:

|----25-----|--55----------|
|......0.......|---------55---|----20--|
|.......0......|---55---------|

x = greatest possible number of households that have all three of these devices = 55

|----25-----|--55-----------|
|.......0......|---------55----|----20--|
|----25-----|---10--|..0.....|---20---|

y = lowest possible number of households that have all three of these devices = 10

x - y = 55 - 10 = 45

IMO C
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