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30 Jun 2016, 07:56
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (01:49) correct
24%
(01:38)
wrong
based on 111
sessions
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In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (8, 0), (0, -3.5), (-8, 0)?
A. 56
B. 88
C. 112
D. 116
E. 120
A. 56
B. 88
C. 112
D. 116
E. 120
Senthil1981
Joined: 23 Apr 2015
Last visit: 14 Oct 2021
Posts: 225
Given Kudos: 36
Location: United States
Concentration: General Management, International Business
Schools: Booth PT '19 Ross Weekend"19
WE:Engineering (Consulting)
30 Jun 2016, 08:13
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Answer is A : 56
Refer to diagram, and it can be broken down to 4 identical triangles with base as 8 and height as 3.5.
So total area =\(4 * 1/2 * 8 * 3.5 = 56\)
Refer to diagram, and it can be broken down to 4 identical triangles with base as 8 and height as 3.5.
So total area =\(4 * 1/2 * 8 * 3.5 = 56\)
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30 Jun 2016, 09:14
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Bunuel
Ares of rhombus= 1/2* D1 *D2
Length of 1st diagonal = 8+8= 16
Length of 2nd diagonal= 3.5+3.5= 7
Area= 1/2*16*7= 56
A is the answer
