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Updated on: 19 Jan 2019, 04:57
Originally posted by mrr0821 on 18 Jan 2019, 04:01.
Last edited by Gladiator59 on 19 Jan 2019, 04:57, edited 1 time in total.
Last edited by Gladiator59 on 19 Jan 2019, 04:57, edited 1 time in total.
Edited OA.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:40) correct
31%
(01:41)
wrong
based on 213
sessions
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Time
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There are three courses to be taken and 32 students on average in each course. 5 students take two courses only and 3 students take all three courses. How many students are there in total?
(a) 91
(b) 88
(c) 94
(d) 85
(e) 92
(a) 91
(b) 88
(c) 94
(d) 85
(e) 92
Updated on: 20 Jan 2019, 04:24
Originally posted by MahmoudFawzy on 19 Jan 2019, 01:37.
Last edited by MahmoudFawzy on 20 Jan 2019, 04:24, edited 1 time in total.
Last edited by MahmoudFawzy on 20 Jan 2019, 04:24, edited 1 time in total.
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by drawing, I found the answer to be 85 (D)
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19 Jan 2019, 01:55
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Sum of individual - (present in exactly two) - 2*(present in all three) = total unique.
This can be seen from the fact that: those who are common to exactly two, are counted twice when we add up the individual ( and hence we need to subtract once)
And those who are common to all three get added thrice. ( Hence subtract twice)
32*3 - 5 - 3*2
96 - 5 - 6 =85
85 seems to be the unique students. Hence (D) should be the correct answer.
mrr0821, what is the source of the question?
This can be seen from the fact that: those who are common to exactly two, are counted twice when we add up the individual ( and hence we need to subtract once)
And those who are common to all three get added thrice. ( Hence subtract twice)
32*3 - 5 - 3*2
96 - 5 - 6 =85
85 seems to be the unique students. Hence (D) should be the correct answer.
mrr0821, what is the source of the question?
