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08 Jul 2019, 14:09
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Hello everyone!
Sorry if i posted this topic in incorrect branch.
So, i understood that i had to calculate the are of the given triangle from using different bases and heights.
1. Area = 1/2*12*3=18
2. Area = 1/2*x*7=12 which yields x=36/7
BUT
I see here a quadrilateral ABCD (as i shown on the picture, which is rectangle as we have two opposite right angles there) and, according to that, x should be equal to 3.
Please, help me to stop seeing here a rectangle. Explain, why it is NOT a rectangle.
Thanks in advance and have a nice day!
Sorry if i posted this topic in incorrect branch.
So, i understood that i had to calculate the are of the given triangle from using different bases and heights.
1. Area = 1/2*12*3=18
2. Area = 1/2*x*7=12 which yields x=36/7
BUT
I see here a quadrilateral ABCD (as i shown on the picture, which is rectangle as we have two opposite right angles there) and, according to that, x should be equal to 3.
Please, help me to stop seeing here a rectangle. Explain, why it is NOT a rectangle.
Thanks in advance and have a nice day!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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08 Jul 2019, 14:56
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1. CB(3) is not equal to AD(36/7). {opposite sides are not equal}
2. Angle CBA is equals to \(π-cos^{-1}(3/7)\), hence all angles of given quadrilateral are not equal to 90*, and CB is not parallel to AD.
2. Angle CBA is equals to \(π-cos^{-1}(3/7)\), hence all angles of given quadrilateral are not equal to 90*, and CB is not parallel to AD.
plk
08 Jul 2019, 15:04
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Yes, i was mistaken suggesting that if two opposite sides of the quadrilateral are equal to 90 it defenetely should be a rectangle. (I tried to draw it but wasn't able to do. Tried after pause and did it successfully)
Sorry for being a bit stupid : )
Sorry for being a bit stupid : )
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
