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13 Oct 2019, 00:46
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76% (01:27) correct
24%
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Triangle ABC has the following vertices : A(1,0), B(5,0), C(3,4). Which of the following is true?
a. AC=BC
b. AB=AC
c. AC>BC
d. AC<BC
e. AB=BC
Posted from my mobile device
a. AC=BC
b. AB=AC
c. AC>BC
d. AC<BC
e. AB=BC
Posted from my mobile device
13 Oct 2019, 01:02
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jackfr2
The sides of the triangle will be ..
(1) AC - A(1,0), C(3,4) -- \(\sqrt{(3-1)^2+(4-0)^2}=\sqrt{4+16}=\sqrt{20}\)
(2) AB - A(1,0), B(5,0) -- \(\sqrt{(5-1)^2+(0-0)^2}=\sqrt{4^2}=\sqrt{16}\)
(3) BC - B(5,0), C(3,4) -- \(\sqrt{(3-5)^2+(4-0)^2}=\sqrt{4+16}=\sqrt{20}\)
So, AC=BC > AB
A
