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Updated on: 24 May 2020, 20:44
Originally posted by mmejiaherrera on 24 May 2020, 17:46.
Last edited by chetan2u on 24 May 2020, 20:44, edited 1 time in total.
Last edited by chetan2u on 24 May 2020, 20:44, edited 1 time in total.
Corrected the OA
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:37) correct
33%
(01:58)
wrong
based on 6
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Let ABCD be a parallelogram. Determine the area of the DOC triangle that is contained in it.
(1) The area of the parallelogram is 84 cm2.
(2) "O" is the point that is exactly in the middle of the AB side.
(1) The area of the parallelogram is 84 cm2.
(2) "O" is the point that is exactly in the middle of the AB side.
I think the answer is "E" because I do not have an indication of the proportion of the base and height values, and the area A=b*a=84*1=42*2=28*3=21*4=14*6=12*7=84. I don't understand why the official answer is "A".
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24 May 2020, 20:29
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Whoever wrote this made an assumption that O lies somewhere on AB.
Statement 1.
Area of parallelogram = h*CD = 84
It doesn't matter where O lies on AB; Height of altitude drawn from O to CD is always equal to h.
Area of DOC = 1/2*h * CD = 42
Sufficient
Statement 2- We don't know any dimension of parallelogram or triangle; We can't find area.
Insufficient
Statement 1.
Area of parallelogram = h*CD = 84
It doesn't matter where O lies on AB; Height of altitude drawn from O to CD is always equal to h.
Area of DOC = 1/2*h * CD = 42
Sufficient
Statement 2- We don't know any dimension of parallelogram or triangle; We can't find area.
Insufficient
mmejiaherrera
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Untitled.png [ 2.98 KiB | Viewed 768 times ]
24 May 2020, 20:44
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mmejiaherrera
The way it is written, the answer should be C.
See the sketch O can be anywhere, so area could be anything.
(1) The area of the parallelogram is 84 cm2.
But we do not know where does O lie. We know CD is common but the height is not known.
(2) "O" is the point that is exactly in the middle of the AB side.
Now we know that the area of ABCD = CD*h. and area of DOC=\(\frac{1}{2}*CD*h\), so half of ABCD.
But we do not know the area of parallelogram.
Combined.
Area = 42
C
Attachments
Untitledaba.png [ 8.06 KiB | Viewed 742 times ]
