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Updated on: 14 Oct 2019, 07:03
Originally posted by sunny4frenz on 20 Sep 2009, 09:32.
Last edited by Bunuel on 14 Oct 2019, 07:03, edited 3 times in total.
Last edited by Bunuel on 14 Oct 2019, 07:03, edited 3 times in total.
Edited the question and added the OA
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
82% (01:33) correct
18%
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A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchase cake mix, 40 purchase muffin mix, and 20 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
A. 1/10
B. 3/10
C. 1/2
D. 7/10
E. 9/10
A. 1/10
B. 3/10
C. 1/2
D. 7/10
E. 9/10
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17 Feb 2012, 08:10
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A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchase cake mix, 40 purchase muffin mix, and 20 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
A. 1/10
B. 3/10
C. 1/2
D. 7/10
E. 9/10
Total = {cake} + {muffin} - {both} + {neither}
100 = 50 + 40 - 20 + {neither} --> {neither} = 30 --> \(\frac{neither}{total}=\frac{30}{100}=\frac{3}{10}\).
Answer: B.
Hope it helps.
A. 1/10
B. 3/10
C. 1/2
D. 7/10
E. 9/10
Total = {cake} + {muffin} - {both} + {neither}
100 = 50 + 40 - 20 + {neither} --> {neither} = 30 --> \(\frac{neither}{total}=\frac{30}{100}=\frac{3}{10}\).
Answer: B.
Hope it helps.
General Discussion
02 Jul 2012, 00:01
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Bunuel
Bunuel,
I have a question. I got this right, but I still think I'm missing something. If you considered this in a Venn-diagram format, it would be clear that there can be buyer who purchase cake mix and bread mix or muffin mix and bread mix. This would alter the equation somewhat. And I noticed that you didn't consider this. Can you please explain why?
