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21 Sep 2020, 04:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
56% (01:51) correct
44%
(02:03)
wrong
based on 448
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In a class, 60% of students play soccer or basketball. If 10% play both sports and 60% do not play soccer, what is the probability that a student chosen at random from the class plays basketball only?
A. 0.1
B. 0.2
C. 0.3
D. 0.4
E. 0.5
A. 0.1
B. 0.2
C. 0.3
D. 0.4
E. 0.5
yashikaaggarwal
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Joined: 19 Jan 2020
Last visit: 29 Mar 2026
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WE:Analyst (Internet and New Media)
21 Sep 2020, 05:39
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Let Total no. of students = 100
the probability that a student chosen at random from the class plays basketball only = Students playing only Basketball/ total no. of students = 20/100 = 0.2
Answer is B
the probability that a student chosen at random from the class plays basketball only = Students playing only Basketball/ total no. of students = 20/100 = 0.2
Answer is B
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11 Oct 2020, 03:38
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Let the total number of students be 100.
P(students who do no play soccer)= 60
P(students who play soccer)= 100-60=40
P(students who only play soccer)= P(students who play soccer)- P(students who play both)=40-10=30
P(students who play soccer or basketball)=P(only soccer) + P(only basketball) +P(students who play both)
60=30 + P(only basketball) + 10
P(only basketball)= 60-40=20% = 0.2
P(students who do no play soccer)= 60
P(students who play soccer)= 100-60=40
P(students who only play soccer)= P(students who play soccer)- P(students who play both)=40-10=30
P(students who play soccer or basketball)=P(only soccer) + P(only basketball) +P(students who play both)
60=30 + P(only basketball) + 10
P(only basketball)= 60-40=20% = 0.2
