Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2601:00 PM EDT
-04:00 PM EDT
Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included. Class starts Saturdays Sept. 26, 2026 - Dec. 19, 2026, 1:00pm-4:00pm ES
Sep 2911:00 AM EDT
-01:00 PM EDT
" Description: Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thur Sept. 29, 2026 - Dec. 3, 2026, 11:00am-1:00pm EST
10 Dec 2020, 13:00
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
76% (01:13) correct
24%
(01:48)
wrong
based on 71
sessions
History
Date
Time
Result
Not Attempted Yet
If AB = AC and ∠1 > ∠B, then
(A) ∠B > ∠C
(B) ∠1 > ∠C
(C) BD > AD
(D) AB > AD
(E) ∠ADC > ∠ADB
Attachment:
2020-12-10_13-10-12.png [ 41.54 KiB | Viewed 1949 times ]
10 Dec 2020, 20:24
Kudos
Bookmarks
[quote="Bunuel"]
If AB = AC and ∠1 > ∠B, then
(A) ∠B > ∠C
AB = AC, so ∠B = ∠C. So not true ever.
(B) ∠1 > ∠C
Now ∠B = ∠C and ∠1 > ∠B, so ∠1 > ∠C.....True
(C) BD > AD
A could be at any distance from D.
Need not be true
(D) AB > AD
Now D is between BC, so AB is always greater than AD. So AD will be greater only when it does not lie between B and C, but beyond B or beyond C.
Bunuel, please check. There may be some error as this also should be true and we cannot have two correct options.
(E) ∠ADC > ∠ADB
If D is closer to B than C, ∠ADC will be less than 90 and ∠ADB will be greater than 90. So need not be true.
B if there is some error in D.
If AB = AC and ∠1 > ∠B, then
(A) ∠B > ∠C
AB = AC, so ∠B = ∠C. So not true ever.
(B) ∠1 > ∠C
Now ∠B = ∠C and ∠1 > ∠B, so ∠1 > ∠C.....True
(C) BD > AD
A could be at any distance from D.
Need not be true
(D) AB > AD
Now D is between BC, so AB is always greater than AD. So AD will be greater only when it does not lie between B and C, but beyond B or beyond C.
Bunuel, please check. There may be some error as this also should be true and we cannot have two correct options.
(E) ∠ADC > ∠ADB
If D is closer to B than C, ∠ADC will be less than 90 and ∠ADB will be greater than 90. So need not be true.
B if there is some error in D.
10 Dec 2020, 20:31
Kudos
Bookmarks
If AB = AC and ∠1 > ∠B, then
If AB = AC =>Angle B = Angle C
Since ∠1 > ∠B, so ∠1 > ∠C which makes Option B as True.
(A) ∠B > ∠C
(B) ∠1 > ∠C
(C) BD > AD
(D) AB > AD
(E) ∠ADC > ∠ADB
