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TulikaArya
Joined: 13 Feb 2022
Last visit: 31 May 2024
Posts: 20
Given Kudos: 296
Location: India
Schools: DeGroote (A$)
GPA: 3.54
WE:Management Consulting (Consulting)
Updated on: 16 Jan 2024, 01:28
Originally posted by TulikaArya on 22 Dec 2022, 15:02.
Last edited by Bunuel on 16 Jan 2024, 01:28, edited 3 times in total.
Last edited by Bunuel on 16 Jan 2024, 01:28, edited 3 times in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
61% (03:23) correct
39%
(03:08)
wrong
based on 233
sessions
History
Date
Time
Result
Not Attempted Yet
In an exam, a student attempted 180 MCQs. It was observed that the ratio of the number of questions that were marked correct to the number of questions that were marked incorrect is 3:2. However, 75 percent of the questions, which were not expected to be marked correct, were marked correct and 50 percent of the questions, which were expected to be marked correct, were marked incorrect. Of the questions which were marked incorrect, what approximate percent of the questions were expected to be marked correct?
(A) 60%
(B) 65%
(C) 70%
(D) 75%
(E) 80%
(A) 60%
(B) 65%
(C) 70%
(D) 75%
(E) 80%
22 Dec 2022, 23:14
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tulikas024
We can use a 2*2 matrix to solve this question. The details can be plot on the matrix as shown below -
- Number of questions that were actual correct = \(\frac{3}{5 }* 180 = 105\)
- Number of questions that were actual in-correct = \(\frac{2}{5} * 180 = 72\)
- Number of questions that were expected to be incorrect = x
75 percent of the questions, which were not expected to be marked correct, were marked correct = 0.75x - Number of questions that were expected to be correct = 180-x
50 percent of the questions, which were expected to be marked correct, were marked incorrect = 50% of (180 - x) = 90 - 0.5x
Number of questions that were expected to be correct and were correct ⇒ 90-0.5x = 108 - 0.75x
x = 72
Number of questions that were incorrect, but were expected to be correct = 50% of (180 - 72) = 54
Required % = \(\frac{54}{72} * 100 = 75%\)
Option D
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