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18 Dec 2024, 08:40
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
83% (01:25) correct
16% (00:06) wrong based on 6 sessions
History
Date
Time
Result
Not Attempted Yet
A bullet train leaves Kyoto for Tokyo traveling 240 miles per hour at 12 noon. Ten minutes later, a train leaves Tokyo for Kyoto traveling 160 miles per hour. If Tokyo and Kyoto are 300 miles apart, at what time will the trains pass each other?
(A) 12:40pm
(B) 12:49pm
(C) 12:55pm
(D) 1:00pm
(E) 1:05pm
(A) 12:40pm
(B) 12:49pm
(C) 12:55pm
(D) 1:00pm
(E) 1:05pm
25 Dec 2024, 09:56
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OE
Solve this problem by filling in the RTD chart. Note that the train going from Kyoto to Tokyo leaves first, so its time is longer by 10 minutes, which is 1/6 hour.
Next, write the expressions for the distance that each train travels, in terms of t. Now, sum those distances and set that total equal to 300 miles:
\(240(t+\frac{1}{6})+160t = 300\)
\(240t+40+160t= 300\)
\(\\
400t=260\\
20t=13\\
\)
\(t=\frac{13}{20} \)hours \(= \frac{39}{60}\) hours = 39 minutes
The first train leaves at 12 noon. The second train leaves at 12:10pm. Thirty-nine minutes aȇer the second train has left, at 12:49pm, the trains pass each other.
1.jpg [ 57.35 KiB | Viewed 552 times ]
Solve this problem by filling in the RTD chart. Note that the train going from Kyoto to Tokyo leaves first, so its time is longer by 10 minutes, which is 1/6 hour.
Next, write the expressions for the distance that each train travels, in terms of t. Now, sum those distances and set that total equal to 300 miles:
\(240(t+\frac{1}{6})+160t = 300\)
\(240t+40+160t= 300\)
\(\\
400t=260\\
20t=13\\
\)
\(t=\frac{13}{20} \)hours \(= \frac{39}{60}\) hours = 39 minutes
The first train leaves at 12 noon. The second train leaves at 12:10pm. Thirty-nine minutes aȇer the second train has left, at 12:49pm, the trains pass each other.
Attachment:
1.jpg [ 57.35 KiB | Viewed 552 times ]
