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22 Aug 2025, 05:01
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Dropdown 1: D
Dropdown 2: 75
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The graph shows the worldwide rate of incidence (number of new cases per 100,000 people) of four diseases-Disease A, Disease B, Disease C, and Disease D-from the beginning of 1970 to the end of 1999.
Based on the information provided, from each drop-down menu, select the option that creates the most accurate statement.
From 1970 to 1999, the disease with the greatest increase in the rate of incidence was Disease .
In 1970, the population of a certain city was 250,000 people. Assuming the city's rates of incidence were equal to worldwide rates of incidence at that time, there were approximatively new cases of Disease B in the city.
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Dropdown 1: D
Dropdown 2: 75
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22 Aug 2025, 10:38
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Fairly simple one.
Question 1, look at which color has the highest indent, that disease D
Question 2, in 1970, disease B has 30 cases per 100,000. For a 250,000 population, total number of cases would be 60 for 200,000 and 15 for the 50,000, so 75.
Question 1, look at which color has the highest indent, that disease D
Question 2, in 1970, disease B has 30 cases per 100,000. For a 250,000 population, total number of cases would be 60 for 200,000 and 15 for the 50,000, so 75.
29 Aug 2025, 01:51
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Samé
Drop-down 1:
Since the question asks about the greatest increase in the rate of incidence, we are looking for the curve with the steepest increase from 1970 to 1999, which according to the graph is the dotted blue curve of Disease D.
Drop-down 2:
According to the graph, the rate of Disease B was 30 per 100,000. If the population of a certain city was 250,000 people, then the absolute number of cases would have been 2.5 times that rate, so 2.5 * 30 = 75.
