deanthedaydreamer
Can anyone help me with this question? It’s from the official focus book for this year
This question is discussed in detail here:
list-s-consists-of-10-consecutive-odd-integers-and-list-t-consists-of-166833.htmlList S consists of 10 consecutive odd integers, and list T consists of 5 consecutive even integers. If the least integer in S is 7 more than the least integer in T, how much greater is the average (arithmetic mean) of the integers in S than the average of the integers in T?
(A) 2
(B) 7
(C) 8
(D) 12
(E) 22
For any evenly spaced set median = mean = the average of the first and the last terms.
So the mean of S will be the average of the first and the last terms: mean = (x + x + 9*2)/2 = x+9, where x is the first term;
The mean of T will simply be the median or the third term: mean = (x - 7) + 2*2 = x - 3;
The difference will be (x + 9) - (x - 3) = 12.
Answer: D.