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How many 3-character alphanumeric sequences can appear as the 5th, 6th, and 7th characters of a valid CID under Proposal 2?
I've attached three files showing the complete question and resources. The correct answer it says is 46,656 which would be 36x36x36. However proposal 2 has a 'character transformer' that replaces the characters: r, s, t, a, i, o, u with the characters s, t, r, e, e, e, e respectively. I'm confused because this transformation will reduce the character options to 32 unique identifiers and thus the answer to 32x32x32 (which is not an option)
Is the question wrong or am I missing something?
Please help, very confused by this
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Attachments
Gmat q3.png [ 214.74 KiB | Viewed 562 times ]
GMAt Q2.png [ 137.54 KiB | Viewed 561 times ]
GMAT Question1.png [ 186.27 KiB | Viewed 562 times ]
How many 3-character alphanumeric sequences can appear as the 5th, 6th, and 7th characters of a valid CID under Proposal 2?
I've attached three files showing the complete question and resources. The correct answer it says is 46,656 which would be 36x36x36. However proposal 2 has a 'character transformer' that replaces the characters: r, s, t, a, i, o, u with the characters s, t, r, e, e, e, e respectively. I'm confused because this transformation will reduce the character options to 32 unique identifiers and thus the answer to 32x32x32 (which is not an option)
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.