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tonebeeze
I got this problem correct using DS guessing theory. I reviewed the answer explanation in the m24, but I still did not fully understand. Can someone flesh out statement 2 for me. Thanks!

Price increased by M% from 1991 to 1992 and by N% from 1992 to 1993. What was the percentage increase in price from 1991 to 1993?

1. MN = 300

2. 100M + 100N + MN = 4300

Hi, would you mind explaining what exactly is DS guessing theory? Could you kindly elaborate more on this?
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tonebeeze
I got this problem correct using DS guessing theory. I reviewed the answer explanation in the m24, but I still did not fully understand. Can someone flesh out statement 2 for me. Thanks!
Price increased by M% from 1991 to 1992 and by N% from 1992 to 1993. What was the percentage increase in price from 1991 to 1993?

1. MN = 300

2. 100M + 100N + MN = 4300

Hi, would you mind explaining what exactly is DS guessing theory? Could you kindly elaborate more on this?
Let price on 1991 be P
in 1992=P(1+m/100)
1993=P(1+m/100)(1+n/100)
%increase= change(1993)-original(1991)/original(1991)
=P(1+m/100)(1+n/100)-P/P
P cancels out.
(1+m/100)(1+n/100)-1
(10^4+100m+100n+mn-10^4)/10^4
(100m+100n+mn)/10^4------(a)
Given in (2) 100m+100n+mn=4300-------->m+n+mn/100=43----(b)
taking 100 out common from (a)
(m+n+mn/100)/10^2
substituting from(b) we get
43/100
43%
Ans B
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There is a formula for cumulative percentage changes:

a + b + ab/100 = total percentage change
a = first period change
b = second period change.

In statement (2) we are simply given this formula, multiplied by 100.

100M + 100N + MN = 4300

equals

M + N + MN/100 = 43

The cumulative increase is 43 %.
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Let's solve this as GMAT Data Sufficiency.
Let the price in 1991 be 100.
Step 1: Apply the percentage increases
From 1991 → 1992, price becomes:
100(1+m100)100\left(1+\frac m{100}\right)
From 1992 → 1993, it increases by n%n\%:
100(1+m100)(1+n100)100\left(1+\frac m{100}\right)\left(1+\frac n{100}\right)
Expand:
=100+m+n+mn100=100+ m+n+\frac{mn}{100}
Therefore, the total percentage increase from 1991 → 1993 is:
m+n+mn100\boxed{m+n+\frac{mn}{100}}
So we need to determine m+n+mn100m+n+\frac{mn}{100}.


Statement (1)
mn=300mn=300
We know the product, but not m+nm+n.
For example:
  • m=10,n=30m=10,n=30 → m+n=40m+n=40
  • m=15,n=20m=15,n=20 → m+n=35m+n=35
Both have mn=300mn=300, but give different total increases.
❌ Statement (1) alone is NOT sufficient.


Statement (2)
100m+100n+mn=4300100m+100n+mn=4300
Divide everything by 100:
m+n+mn100=43m+n+\frac{mn}{100}=43
But that's exactly the total percentage increase!
Therefore:
43%\boxed{43\%}
So statement (2) alone is sufficient.
✅ Statement (2) is sufficient.


Answer: B
Statement (2) alone is sufficient.
The shortcut to remember
For two successive percentage increases:
Total increase=m+n+mn100\boxed{\text{Total increase}=m+n+\frac{mn}{100}}
So when you see:
100m+100n+mn100m+100n+mn
you should immediately recognize:
100×Total increase100\times\text{Total increase}
Here:
4300100=43%\frac{4300}{100}=\boxed{43\%}

Bunuel
Price increased by \(m\%\) from 1991 to 1992 and by \(n\%\) from 1992 to 1993. What was the percentage increase in price from 1991 to 1993?

(1) \(mn = 300\)

(2) \(100m + 100n + mn = 4300\)



M24-19

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