Let's solve this as
GMAT Data Sufficiency.
Let the price in 1991 be
100.
Step 1: Apply the percentage increases
From 1991 → 1992, price becomes:
100(1+m100)100\left(1+\frac m{100}\right)
From 1992 → 1993, it increases by n%n\%:
100(1+m100)(1+n100)100\left(1+\frac m{100}\right)\left(1+\frac n{100}\right)
Expand:
=100+m+n+mn100=100+ m+n+\frac{mn}{100}
Therefore, the
total percentage increase from 1991 → 1993 is:
m+n+mn100\boxed{m+n+\frac{mn}{100}}
So we need to determine m+n+mn100m+n+\frac{mn}{100}.
Statement (1)
mn=300mn=300
We know the product, but
not m+nm+n.
For example:
- m=10,n=30m=10,n=30 → m+n=40m+n=40
- m=15,n=20m=15,n=20 → m+n=35m+n=35
Both have mn=300mn=300, but give different total increases.
❌
Statement (1) alone is NOT sufficient.
Statement (2)
100m+100n+mn=4300100m+100n+mn=4300
Divide everything by 100:
m+n+mn100=43m+n+\frac{mn}{100}=43
But that's
exactly the total percentage increase!
Therefore:
43%\boxed{43\%}
So statement (2) alone is sufficient.
✅
Statement (2) is sufficient.
Answer:
BStatement (2) alone is sufficient.The shortcut to remember
For two successive percentage increases:
Total increase=m+n+mn100\boxed{\text{Total increase}=m+n+\frac{mn}{100}}
So when you see:
100m+100n+mn100m+100n+mn
you should immediately recognize:
100×Total increase100\times\text{Total increase}
Here:
4300100=43%\frac{4300}{100}=\boxed{43\%}
Bunuel
Price increased by \(m\%\) from 1991 to 1992 and by \(n\%\) from 1992 to 1993. What was the percentage increase in price from 1991 to 1993?
(1) \(mn = 300\)
(2) \(100m + 100n + mn = 4300\)
M24-19
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