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# Probability

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Manager
Joined: 11 Apr 2009
Posts: 160

Kudos [?]: 114 [0], given: 5

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20 May 2009, 18:43
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Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?
5/6
2/3
1/2
5/12
1/3

I could not understand the question and hence had problems with figuring out the answer to this.........

Kudos [?]: 114 [0], given: 5

SVP
Joined: 07 Nov 2007
Posts: 1792

Kudos [?]: 1061 [0], given: 5

Location: New York

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20 May 2009, 21:50
gmatprep09 wrote:
Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?
5/6
2/3
1/2
5/12
1/3

I could not understand the question and hence had problems with figuring out the answer to this.........

Without solving also we can guess answer to this question : 1/3

chances of Jim Win: 1/3
chances of Renee win:1/3
chance of draw :1/3

these below are the wining combination when both of them chose one of the card
R>S
S>P
P>R

e.g Jim choose R and Renee choose S --> Jim Wins

probablity= 1/3*1/3 (J choosing R and R chooses S)+1/3*1/3+1/3*1/3
=1/3
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Kudos [?]: 1061 [0], given: 5

Re: Probability   [#permalink] 20 May 2009, 21:50
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