GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 09 Apr 2020, 20:17

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Probability and Problem Solving

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Intern
Joined: 28 Aug 2019
Posts: 1
Probability and Problem Solving  [#permalink]

### Show Tags

16 Feb 2020, 20:15
The probability of Alice hitting the target while shooting is 0.4 and probability of either Alice, Ban or both hitting the target is 0.8.
I) What is the probability of Ban hitting the target, if both events are mutually exclusive?
II) What is the probability of Ban hitting the target, if both events are independent?

Posted from my mobile device
AWA Forum Moderator
Status: Manager
Joined: 27 Oct 2018
Posts: 808
Location: Egypt
Concentration: Strategy, International Business
GPA: 3.67
WE: Pharmaceuticals (Health Care)
Re: Probability and Problem Solving  [#permalink]

### Show Tags

16 Feb 2020, 22:58
1
sark19 wrote:
The probability of Alice hitting the target while shooting is 0.4 and probability of either Alice, Ban or both hitting the target is 0.8.
I) What is the probability of Ban hitting the target, if both events are mutually exclusive?
II) What is the probability of Ban hitting the target, if both events are independent?

Posted from my mobile device

if mutually exclusive:
we can put it in the table shown.
we can't find B because of insufficient info

if independent:
$$A = 0.4$$
$$A∪B = A + B - A∩B = 0.8$$
$$A∩B= A*B = 0.4B$$

$$B - 0.4B = 0.4$$
$$0.6B = 0.4$$
$$B = \frac{2}{3}$$
Attachments

aaa.png [ 2.19 KiB | Viewed 310 times ]

Senior Manager
Joined: 09 Jan 2017
Posts: 317
Location: India
Re: Probability and Problem Solving  [#permalink]

### Show Tags

17 Feb 2020, 05:05
1
MahmoudFawzy, what basically the equation will be as follows

if mutually exclusive:

P(the target is hit) = P(A)P(B')+P(B)P(A')
as we don't know P(B), we cant determine the answer
am i correct?
SC Moderator
Joined: 25 Sep 2018
Posts: 719
Location: United States (CA)
Concentration: Finance, Strategy
GPA: 3.97
WE: Investment Banking (Investment Banking)
Probability and Problem Solving  [#permalink]

### Show Tags

17 Feb 2020, 05:43
Hi, Kindly repost the question according to the rules: https://gmatclub.com/forum/rules-for-po ... 33935.html

This topic is locked.
_________________
Need a last minute SC revision guide? Click here

Whatever it takes...Until your spirit Breaks
AWA Forum Moderator
Status: Manager
Joined: 27 Oct 2018
Posts: 808
Location: Egypt
Concentration: Strategy, International Business
GPA: 3.67
WE: Pharmaceuticals (Health Care)
Re: Probability and Problem Solving  [#permalink]

### Show Tags

17 Feb 2020, 16:37
J2S2019 wrote:
MahmoudFawzy, what basically the equation will be as follows

if mutually exclusive:

P(the target is hit) = P(A)P(B')+P(B)P(A')
as we don't know P(B), we cant determine the answer
am i correct?

For Independent or Exclusive, the same equation applies:
P(hit) = P(A)(B) + P(A)(B') + P(B)(A')

The difference is in calculating P(A)(B) and P(A')(B'), which can be calculated by multiplication in case of independent but not in Exclusive.
SVP
Joined: 20 Jul 2017
Posts: 1509
Location: India
Concentration: Entrepreneurship, Marketing
WE: Education (Education)
Re: Probability and Problem Solving  [#permalink]

### Show Tags

18 Feb 2020, 11:27
sark19 wrote:
The probability of Alice hitting the target while shooting is 0.4 and probability of either Alice, Ban or both hitting the target is 0.8.
I) What is the probability of Ban hitting the target, if both events are mutually exclusive?
II) What is the probability of Ban hitting the target, if both events are independent?

Posted from my mobile device

I) What is the probability of Ban hitting the target, if both events are mutually exclusive?
Mutually exclusive—> P(A&B) = 0
—> P(A) + P(B) - P(A&B) = 0.8
—> 0.4 + P(B) - 0 = 0.8
—> P(B) = 0.4
Re: Probability and Problem Solving   [#permalink] 18 Feb 2020, 11:27
Display posts from previous: Sort by

# Probability and Problem Solving

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne