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Probability question

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Probability question  [#permalink]

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New post 07 Apr 2018, 13:56
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A basket contains 10 fruits of which 4 are rotten. If 3 fruits are drawn from the basket, find the probability that none of the fruits drawn is rotten.
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Joined: 16 Mar 2018
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Re: Probability question  [#permalink]

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New post 07 Apr 2018, 14:51
Out of 10 fruits 6 are non rotten.

For fruits to be drawn 3 times,
Out of 6 fruits is same as
Drawing out of 6 fruits first time

So Prob= 6/10 = 3/5

Drawing out of remaining 5 fruits second time

So prob = 5/9


Drawing third time out of remaining 8fruits

So Prob = 4/8=1/2

To get Total Probability we multiply

3/5 x 5/9 x 1/2 = 1/6



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Re: Probability question  [#permalink]

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New post 08 Apr 2018, 00:52
What I think is:

According to the language of the question, 3 fruits are drawn simultaneously from the basket and are not drawn one by one.

Hence, P(none of the fruits drawn is rotten) = P (drawing a non-rotten fruit)= 6C3/10C3 = 1/6
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Re: Probability question  [#permalink]

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New post 08 Apr 2018, 11:48
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Re: Probability question   [#permalink] 08 Apr 2018, 11:48
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