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A club has 10 members. They will first pick a president then a secretary then a treasure. What is the probability that a given person is selected as secretary or treasurer.
I thought about it this way. First you much not be selected as president this is a 9/10 chance. Then you have a 1/9 and 1/8 chance to be selected as one of the other positions. so 9/10*(1/9+ 1/8)
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A club has 10 members. They will first pick a president then a secretary then a treasure. What is the probability that a given person is selected as secretary or treasurer.
I thought about it this way. First you much not be selected as president this is a 9/10 chance. Then you have a 1/9 and 1/8 chance to be selected as one of the other positions. so 9/10*(1/9+ 1/8)
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Think about it this way: say you have to pick a number between one and four, inclusive. What's the probability that you pick either 1 or 2?
The answer is pretty obvious:
Probability that you choose 1: \(1/4\) Probability that you choose 2: \(1/4\) Probability that you choose 1 or 2: \(1/4 + 1/4 = 1/2\)
This is the exact same concept as the original problem. It doesn't matter whether you choose the secretary or the treasurer first -- the probability that person A will receive either of the titles is the same.
Probability that person A will be chosen as treasurer: \(1/10\) Probability that person A will be chosen as secretary: \(1/10\) Probability that person A will be chosen as either treasurer or secretary: \(1/10 + 1/10 = 1/5\)
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.