8. Word Problems8.1. A training coach conducted two types of practice sessions on one day: advanced sessions and standard sessions. If the total practice time for the sessions was 210 minutes that day, how many standard sessions were conducted?(1) Each advanced session lasted 49 minutes, and each standard session lasted 28 minutes.
(2) There were 6 sessions in total.
SOLUTION:
A training coach conducted two types of practice sessions on one day: advanced sessions and standard sessions. If the total practice time for the sessions was 210 minutes that day, how many standard sessions were conducted?This is a classic C-trap question. In C-trap questions, the two statements together clearly
appear sufficient, but in reality, one statement alone
may already be enough. Whenever that happens, we have to proceed very carefully. In this question, once the two statements are combined, it is obvious that we have all the information there could be about the problem, so the combination is clearly sufficient. The real issue is whether either statement, or both, is already sufficient on its own.
Let the number of advanced sessions be a and the number of standard sessions be s. The question is: what is the value of s?
(1) Each advanced session lasted 49 minutes, and each standard session lasted 28 minutes.
Because the total practice time was 210 minutes, we get:
49a + 28s = 210
Reducing by 7 gives:
7a + 4s = 30
In general, a linear equation of the form ax + by = c has infinitely many solutions. But here a and s represent numbers of sessions, so they must be non-negative integers. That means we have an equation whose solutions must be integers only. In such cases, we must check directly whether there is just one integer combination that satisfies the equation.
It is not hard to test whether 7a + 4s = 30 has one solution or more than one. Rearranging gives:
4s = 30 - 7a
So 30 minus a multiple of 7 must be divisible by 4:
• 30 is not divisible by 4
• 23 is not
• 16 is divisible by 4 (a = 2, s = 4)
• 9 is not
• 2 is not
So there is only one pair of values of a and s that satisfies 7a + 4s = 30, namely a = 2 and s = 4. Sufficient.
(2) There were 6 sessions in total.
This gives:
a + s = 6
As above, this is also an equation whose solutions must be integers only. But unlike statement (1), this equation has several integer solutions for a and s. Therefore, it is clearly not sufficient to determine a single value of s.
Answer: A.
TakeawayIn Data Sufficiency, you should be alert to C-trap questions. These are questions in which the two statements together clearly seem sufficient, but in fact, one statement alone may already be enough. When that happens, we should proceed carefully and not fall for the C-trap.
Also, for a linear equation in two variables, we should not automatically conclude that it has infinitely many solutions. We must pay attention to the constraints, especially the domain of the variables, because those constraints can sharply reduce the number of valid solutions. In a question like this, the variables represent counts, so they must be non-negative integers. Because of that restriction, a linear equation that would otherwise have infinitely many solutions can end up having only one valid pair of values.
What This Question TestsThis question tests word problems, specifically a special type of Data Sufficiency word problem known as a C-trap question, as well as linear equations with integer-restricted solutions. It also tests whether you notice that the variables represent counts, so the non-negative integer restriction is essential to determining whether a statement is sufficient.