Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
06 Oct 2011, 03:38
Kudos
Bookmarks
A cylinder tank with radius of the base 1 and height 2 is half full of water. If all the water is poured into another cylinder tank with height 1 and radius of the base 2, to what percent of its capacity will this new tank be filled?
(C) 2008 GMAT Club - m25#37
(A) 20%
(B) 25%
(C) 32%
(D) 35%
(E) 40%
(C) 2008 GMAT Club - m25#37
(A) 20%
(B) 25%
(C) 32%
(D) 35%
(E) 40%
Archived Topic
Hi there,
Archived GMAT Club Tests question - no more replies possible.
Where to now? Try our up-to-date Free Adaptive GMAT Club Tests
for the latest questions.
Still interested? Check out the "Best Topics" block below for better discussion and related questions.
Thank you for understanding, and happy exploring!
06 Oct 2011, 04:19
Kudos
Bookmarks
kkalyan
Volume of a cylinder= \(\pi*r^2*h\)
Volume of a cylinder 1= \(\pi*(1)^2*2=2 \pi\). Since the tank is half filled, Volume of water=\(\frac{2 \pi}{2}=\pi\)
Volume of a cylinder 2= \(\pi*(2)^2*1=4 \pi\)
% of water in 2= [(Volume of water)/(Volume of a cylinder 2)]*100
% of water in 2 \(=\frac{\pi}{4 \pi}*100=25%\)
Ans: "B"
06 Oct 2011, 07:27
Kudos
Bookmarks
vol of cylinder1 = \(\pi*r^2h = 2\pi\)
vol of cylinder2 = \(\pi*r^2h = 4\pi\)
vol of cyl2 is twice that of cyl1. so if cyl1 is 1/2 filled then cyl2 must be \(\frac{1}{4}\) filled i.e. 25%
vol of cylinder2 = \(\pi*r^2h = 4\pi\)
vol of cyl2 is twice that of cyl1. so if cyl1 is 1/2 filled then cyl2 must be \(\frac{1}{4}\) filled i.e. 25%
