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# PS 299 OG10 explanation & inequalities

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PS 299 OG10 explanation & inequalities [#permalink]

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08 Dec 2008, 12:25
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In the explanation to PS299, OG10 says in point II " -1 < - c/d < 1 .... is equivalent to 0 < c/d < 1 ".

How do we go from ( -1 < -c/d < 1 ) to ( 0 < c/d < 1 ) ?

Thanks

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Re: PS 299 OG10 explanation & inequalities [#permalink]

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08 Dec 2008, 18:02
cowalko wrote:
In the explanation to PS299, OG10 says in point II " -1 < - c/d < 1 .... is equivalent to 0 < c/d < 1 ".

How do we go from ( -1 < -c/d < 1 ) to ( 0 < c/d < 1 ) ?

Thanks

is the question complete?

specify c and d?
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Re: PS 299 OG10 explanation & inequalities [#permalink]

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08 Dec 2008, 19:20
yes, it's complete: ( -1 < -c/d < 1 ) = ( 0 < c/d < 1 ) why?

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Re: PS 299 OG10 explanation & inequalities [#permalink]

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08 Dec 2008, 19:39
cowalko wrote:
yes, it's complete: ( -1 < -c/d < 1 ) = ( 0 < c/d < 1 ) why?

does it say c, d are positive integer?

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Re: PS 299 OG10 explanation & inequalities [#permalink]

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09 Dec 2008, 08:02
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Quote:
In the explanation to PS299, OG10 says in point II

"-1 < -c/d < 1" .... is equivalent to "0< c/d < 1"
Suppose that "if d>0"
How do we go from ( -1 < -c/d < 1 ) to ( 0 < c/d < 1 )?

Even if d>0 and (-1 < -c/d < 1), c could be -ve or 0 or +ve and similarly c/d is also a +ve or -ve fraction.

I guess the question is still not complete cuz C has to be none-zero number, which is smaller than d.

The question is still not complete. Make sure the question is posted completely.
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Re: PS 299 OG10 explanation & inequalities [#permalink]

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09 Dec 2008, 18:05
Agree that the question is not complete
for example if you take c/d=-0.5 one inequality does not resolve to the other.

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Re: PS 299 OG10 explanation & inequalities [#permalink]

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11 Dec 2008, 09:34
I´ll check it and try to find out what's missing.
Thanks anyway

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Re: PS 299 OG10 explanation & inequalities   [#permalink] 11 Dec 2008, 09:34
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# PS 299 OG10 explanation & inequalities

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