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beyondinfinity
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Good one. I slipped up and selected E :cry:
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Initially the set is
680,450(Ann),360,210,190(Cal)

After correction the distribution must be
680,360,330,210,x

So we must deduct 120 from Ann's for the median to be 330. Hence answer is D
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Given set of #s

Sorted : 190, 210, 360, 450, 680
Seller : C, D, B, A, E

As it stands median is 360. If A's actual sales is 450-x and C actual sales is 190+x, then

450-x = 330 (the new median)
i.e x = 120

New order :
210, 310, 330, 360, 680
D, C, A, B, E

Answer : D 120,000
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Either Cal has a total sales of 330,000 or Ann has total sales of 330,000.

In case 1.

If Cal has total sales of 330,000 then there is an increase of 140,000. THe same amount will be subtracted from Ann. So Ann is left with 310,000

Which is less than Cal hence doesnot satisfy the condition

In case 2.

If Ann has total sales of 330,000 the differece is 120,000. Cal has 310,000

satisfies the conditions hence 120,000



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