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27 Nov 2006, 09:25
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In a certain test, a student must answer 8 out of 10 questions. How many choices are there if at least 4 of the first five questions must be answered?
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In a certain test, a student must answer 8 out of 10 questions. How many choices are there if at least 4 of the first five questions must be answered
4 from 1st and 4 from 2nd = 5C4*5C4=25
4 from 1st and 5 from 2nd = 5c4*5c5=5
5 from 1st and 3 from 2nd = 5C5*5c3=10 coorected for combi
5 from 1st and 4 from 2nd = 5c5*5c4=5
5 from 1st and 5 from 2nd =5c5*5c5=1
[Total 41
4 from 1st and 4 from 2nd = 5C4*5C4=25
4 from 1st and 5 from 2nd = 5c4*5c5=5
5 from 1st and 3 from 2nd = 5C5*5c3=10 coorected for combi
5 from 1st and 4 from 2nd = 5c5*5c4=5
5 from 1st and 5 from 2nd =5c5*5c5=1
[Total 41
27 Nov 2006, 09:38
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If student has to answer ONLY 8 out of 10 then:
1) Number of ways of answering 4 out of first 5 Qs = 5C4 = 5
2) Number of ways of answering 5 out of first 5 Qs = 5C5 = 1
Number of ways of answering 4 (from 1) out of last 5 Qs = 5C4 = 5
Number of ways of answering 3 (from 2) out of last 5 Qs = 5C3 = 10
Total number of ways if 4 out of first 5 Qs are answered = 5*5 = 25
Total number of ways if 5 out of first 5 Qs are answered = 1*10 = 10
25+10 = 35 total possibilities
OA?
1) Number of ways of answering 4 out of first 5 Qs = 5C4 = 5
2) Number of ways of answering 5 out of first 5 Qs = 5C5 = 1
Number of ways of answering 4 (from 1) out of last 5 Qs = 5C4 = 5
Number of ways of answering 3 (from 2) out of last 5 Qs = 5C3 = 10
Total number of ways if 4 out of first 5 Qs are answered = 5*5 = 25
Total number of ways if 5 out of first 5 Qs are answered = 1*10 = 10
25+10 = 35 total possibilities
OA?
