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13 Jan 2021, 09:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (01:26) correct
24%
(01:38)
wrong
based on 37
sessions
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On completely immersing a solid metal sphere into a cylindrical bucket partially filled with water, the level of water rose 1cm without overflow. If the internal radius of the bucket is 6cm, what is the radius of the sphere?
A. 0.5
B. 1
C. 2
D. 3
E. 4
A. 0.5
B. 1
C. 2
D. 3
E. 4
shubhs76
Joined: 20 Nov 2020
Last visit: 04 Apr 2023
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Location: India
Concentration: Marketing
Schools: HEC Jan 23 Intake (D) IE SDA Bocconi "24
GPA: 3
WE:Marketing (Telecommunications)
13 Jan 2021, 09:29
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As the water level rose by 1, so we assume the volume of cylinder with height 1 and radius 6 (radius of bucket) is equal to the volume of the sphere.
radius of bucket (r) =6
Height (h) = 1
Substituting the formula, gives radius of sphere (R) as,
πr^2h=4/3πR^3
We get R as 3, option (D)
Posted from my mobile device
radius of bucket (r) =6
Height (h) = 1
Substituting the formula, gives radius of sphere (R) as,
πr^2h=4/3πR^3
We get R as 3, option (D)
Posted from my mobile device
13 Jan 2021, 09:38
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Volume of water increase = volume of sphere
So, pie* 6^2 *1 = 4/3 *pie *r^3 or, r^3 = 27 or r = 3
So, It is D.
So, pie* 6^2 *1 = 4/3 *pie *r^3 or, r^3 = 27 or r = 3
So, It is D.
