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25 Sep 2009, 13:49
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
25% (02:34) correct
75%
(00:00)
wrong
based on 3
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History
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Time
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Not Attempted Yet
Mark is playing poker at a casino. Mark starts playing with
140 chips, 20% of which are $100 chips and 80% of which are
$20 chips. For his first bet, Mark places chips, 10% of
which are $100 chips, in the center of the table. If 70% of
Mark's remaining chips are $20 chips, how much money did
Mark bet?
A. $1,960
B. $1,740
C. $1,540
D. $3,080
E. $2,640
140 chips, 20% of which are $100 chips and 80% of which are
$20 chips. For his first bet, Mark places chips, 10% of
which are $100 chips, in the center of the table. If 70% of
Mark's remaining chips are $20 chips, how much money did
Mark bet?
A. $1,960
B. $1,740
C. $1,540
D. $3,080
E. $2,640
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25 Sep 2009, 14:50
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rlevochkin
Mark is playing poker at a casino. Mark starts playing with
140 chips, 20% of which are $100 chips and 80% of which are
$20 chips. For his first bet, Mark places chips, 10% of
which are $100 chips, in the center of the table. If 70% of
Mark's remaining chips are $20 chips, how much money did
Mark bet?
A. $1,960
B. $1,740
C. $1,540
D. $3,080
E. $2,640
140 chips, 20% of which are $100 chips and 80% of which are
$20 chips. For his first bet, Mark places chips, 10% of
which are $100 chips, in the center of the table. If 70% of
Mark's remaining chips are $20 chips, how much money did
Mark bet?
A. $1,960
B. $1,740
C. $1,540
D. $3,080
E. $2,640
The answer is A. Initially Mark has 14*2 $100 chips and 14*8 $20 chips. Let's say Mark bets x $100 chips and 9x $20 chips -> bet = $280*x
Notice that the number of $100 chips remaining is 14*2-x, which is 0.3 of the total number of remaining chips = 14*10-10*x ->
14*2-x = 0.3*(14*10-10*x)-> x = 7 -> bet = $280*7=$1,960
